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Nataly_w [17]
2 years ago
10

What is the thinnest soap film (excluding the case of zero thickness) that appears black when illuminated with light with a wave

length of 550 nm
Physics
1 answer:
Archy [21]2 years ago
8 0

Answer:

The expression for destructive interference in thin films allows to find the result for the smallest thickness of the films is:

         t = 2.03 10⁻⁸ mm

Explanation:

Given parameters

Incident wavelength lamo = 535 nm

Refractive index of the film n = 1.32

To find

The minimum thickness for destructive interference

The interference phenomenon occurs when the path of two rays scattered by an obstacle have different optical paths. In the case of thin films we must take into account:

The reflected wave has a phase change of 180º when it goes from a medium with a lower refractive index to a medium with a higher index.

Inside the film medium the wavelength is modulated by the refractive index.

                 

In the attachment we see an outline of these events and the expression for destructive interference remains.

               2 n t = m λ₀

Where n is the refractive index, t the thickness of the film, λ₀ the wavelength in the vacuum and m an integer indicating the order of interference.  

             t =  

The first destructive interference occurs for m = 1, let's calculate.

       t =    

       t = 202.65 nm

Let's reduce this amount to millimeters.

        t = 202.65 nm  

        t = 2,027 10⁻⁸ mm

In conclusion, using the expression for destructive interference in thin films we can find the result for the smallest thickness of the films is:

         t = 2.03 10⁻⁸ mm

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Calculator
denpristay [2]

Answer:

25

Explanation:

By Using Pythagoras Theorem,

h^2=p^2+b^2

or, x^2=(24)^2+7^2

or, x^2=576+49

or, x^2=625

or, x=√625

•°• x=25

5 0
3 years ago
Cual es la fuerza electrica sobre el electrón (-1.6 x 10¹⁹c) de un atomo de hidrógeno ejercida por el protón (1.6 x 10¹⁹c)? Supó
kkurt [141]

Answer:

La  fuerza eléctrica es -8.2*10⁻⁸ N

Explanation:

El enunciado correcto es: <em>¿Cuál es la fuerza eléctrica sobre el electrón (-1.6 x 10⁻¹⁹c) de un átomo de hidrógeno ejercida por el protón (1.6 x 10⁻¹⁹c)? Supóngase que la distancia entre el electrón y el protón es de 5.3 x 10⁻¹¹ m</em>

Entre dos o más cargas aparece una fuerza denominada fuerza eléctrica. Su valor depende del valor de las cargas y de la distancia que las separa, mientras que su signo depende del signo de cada carga. Las cargas del mismo signo se repelen entre sí, mientras que las de distinto signo se atraen.

La fuerza eléctrica con la que se atraen o repelen dos cargas puntuales en reposo es directamente proporcional al producto de las mismas e inversamente proporcional al cuadrado de la distancia que las separa:

F=K*\frac{q1*q2}{d^{2} }

donde:

  • F es la fuerza eléctrica de atracción o repulsión. En el Sistema Internacional (S.I.) se mide en Newtons (N).
  • q1 y q2 son lo valores de las dos cargas puntuales. En el S.I. se miden en Culombios (C).
  • d es el valor de la distancia que las separa. En el S.I. se mide en metros (m).
  • K es una constante de proporcionalidad llamada constante de la ley de Coulomb. Depende del medio en el que se encuentren las cargas. Para el vacío K tiene un valor aproximadamente de 9*10⁹ \frac{N*m^{2} }{C^{2} }.

En este caso:

  • F=?
  • K= 9*10⁹ \frac{N*m^{2} }{C^{2} }
  • q1= -1.6*10⁻¹⁹ C
  • q2= 1.6*10⁻¹⁹ C
  • d= 5.3*10⁻¹¹ m

Reemplazando:

F=9*10^{9} \frac{N*m^{2} }{C^{2} }*\frac{(-1.6*10^{19} C)*(1.6*10^{19} C)}{(5.3*10^{-11} )^{2} }

Resolviendo:

F= -8.2*10⁻⁸ N

<u><em>La  fuerza eléctrica es -8.2*10⁻⁸ N</em></u>

6 0
3 years ago
A mass tied to the end of a 1.0 m-long string is swinging back and forth From its lowest point, the mass moves 4 cm to the right
ehidna [41]

Answer:

a) 2seconds.

Explanation:

The period of oscillation will not change . It will still be 2seconds although the length was doubled to 8cm.

This is because the amplitude does not change oscillation time.

5 0
3 years ago
How does reverberation explain why your voice sounds different in a gym than it does in your living room
TEA [102]
Sound can reach the inner ear by way of two separate paths, and those paths in turn affect what we perceive. Air-conducted sound is transmitted from the surrounding environment through the external auditory canal, eardrum and middle ear to the cochlea, the fluid-filled spiral in the inner ear. Bone-conducted sound reaches the cochlea directly through the tissues of the head.
When you speak, sound energy spreads in the air around you and reaches your cochlea through your external ear by air conduction. Sound also travels from your vocal cords and other structures directly to the cochlea, but the mechanical properties of your head enhance its deeper, lower-frequency vibrations. The voice you hear when you speak is the combination of sound carried along both paths. When you listen to a recording of yourself speaking, the bone-conducted pathway that you consider part of your “normal” voice is eliminated, and you hear only the air-conducted component in unfamiliar isolation. You can experience the reverse effect by putting in earplugs so you hear only bone-conducted vibrations.
Some people have abnormalities of the inner ear that enhance their sensitivity to this component so much that the sound of their own breathing becomes overwhelming, and they may even hear their eyeballs moving in their sockets.
6 0
3 years ago
Alice and Bob sit on a see saw, that consists of a uniform beam of mass 20kg and a fulcrum rock, that acts as a pivot point. The
tankabanditka [31]

Answer:

Explanation:

Given

Mass of alice M_a=50 kg

Mass of bob M_b=70 kg

Mass of beam M=20 kg

Suppose fulcrum is at distance of d from bob thus From diagram

Equating torque i.e. torque of Bob,Alice and beam must cancel out each other to be balanced

500\times (8-d)+20\times (4-d)=70\times d

400-50d+80-2d=70d

480=140d

d=\frac{480}{140}

d=3.43 m    

5 0
4 years ago
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