Answer:
The amount to be repaid is $379.26.
Step-by-step explanation:
Period of note from May 1 to December 19 = 233 days
Amount of note or principal = $1,000
Simple interest rate = 8.5%
Maturity date = December 19
Repayments:
June 2 = $475
Nov. 4 = $200
Total paid $675
Simple interest = $54.26 ($1,000 * 8.5% * 233/365)
Total amount to be repaid = $1,054.26
Total amount repaid = 675.00
Balance to be paid on maturity $379.26
Answer: 38.41 minutes
Step-by-step explanation:
The standard error for the difference in means is given by :-
![SE.=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma^2_2}{n_2}}](https://tex.z-dn.net/?f=SE.%3D%5Csqrt%7B%5Cdfrac%7B%5Csigma_1%5E2%7D%7Bn_1%7D%2B%5Cdfrac%7B%5Csigma%5E2_2%7D%7Bn_2%7D%7D)
where ,
= Standard deviation for sample 1.
= Size of sample 1.
= Standard deviation for sample 2.
= Size of sample 2.
Let the sample of Latino name is first and non -Latino is second.
As per given , we have
![n_1=9](https://tex.z-dn.net/?f=n_1%3D9)
![n_2=14](https://tex.z-dn.net/?f=n_2%3D14)
The standard error for the difference in means will be :
![SE.=\sqrt{\dfrac{(82)^2}{9}+\dfrac{(101)^2}{14}}](https://tex.z-dn.net/?f=SE.%3D%5Csqrt%7B%5Cdfrac%7B%2882%29%5E2%7D%7B9%7D%2B%5Cdfrac%7B%28101%29%5E2%7D%7B14%7D%7D)
![SE.=\sqrt{\dfrac{6724}{9}+\dfrac{10201}{14}}](https://tex.z-dn.net/?f=SE.%3D%5Csqrt%7B%5Cdfrac%7B6724%7D%7B9%7D%2B%5Cdfrac%7B10201%7D%7B14%7D%7D)
![SE.=\sqrt{747.111111111+728.642857143}](https://tex.z-dn.net/?f=SE.%3D%5Csqrt%7B747.111111111%2B728.642857143%7D)
![SE.=\sqrt{1475.75396825}=38.4155433158\approx38.41](https://tex.z-dn.net/?f=SE.%3D%5Csqrt%7B1475.75396825%7D%3D38.4155433158%5Capprox38.41)
Hence, the standard error for the difference in means =38.41 minutes
Step-by-step explanation:
it's explained in the solution
Answer:
925 marks.
Step-by-step explanation:
AS Biraj had 20 less marks then the 40% pass mark must be 350+20 = 370.
370 is equivalent to 40%
So 100% = 100*370 / 40
= 925 marks.