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jenyasd209 [6]
2 years ago
11

Determine if the sequence below is arithmetic or geometric and determine

Mathematics
1 answer:
klio [65]2 years ago
5 0

Answer:

It is arithmetic

Step-by-step explanation:

Using the rule T2-T1

We see that 16-22 is -6

We can also try T3-T2

We see that 10-16 is also -6

Their is a constant common difference and that constant common difference is -6.

Hope that helps :)

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"Mia jogs 3 kilometers in 20 minutes. There are about 0.6 miles in a kilometer. What is Mia’s approximate speed in miles per min
Lapatulllka [165]
First we need to find Mia's speed (v) in km/min

v = distance travelled/ time 
v = 3 km/20 minutes
v = 0.15 km /min

in order to convert the speed into mile/min, we need to use the conversion factor given in which for every kilometer, there is 0.6 miles. 

v = 0.15 km/min *(0.6 miles/ km) 
v =0.09 miles/min

therefore the speed in miles/min is 0.09 miles/min
4 0
3 years ago
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A scientist begins an experiment with a culture of 5 bacteria cells. Every hour, the number of bacteria cells triples. Which equ
Liono4ka [1.6K]
Whichever one is 5*3^x.
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3 years ago
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12∙(40-39)+2<br><br> A. 18<br><br> B. 14<br><br> C. 24<br><br> D. 30
monitta

Answer:

B.14

Step-by-step explanation:

7 0
2 years ago
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What are the determinants for solving this linear system?<br> 5x + 3y = 17<br> −8x − 3y = 9
Ksivusya [100]
For this case we have the following system of equations:
 5x + 3y = 17
 -8x - 3y = 9
 We can rewrite the system like:
 Ax = b
 Where,
 A = [5   3; -8   -3]
 b = [17; 9]
 x = [x; y]
 The determinant of matrix A is given by:
 lAl = ((5) * (- 3)) - ((3) * (- 8))
 lAl = (-15) - (-24)
 lAl = -15 + 24
 lAl = 9
 Answer:
 
The determinant for solving this linear system is:
 
lAl = 9
3 0
2 years ago
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The slope-intercept form of the equation of a line that passes through point (-3, 8) is y = -2/3x + 6. What is the point-
Elena-2011 [213]

y = \stackrel{\stackrel{m}{\downarrow }}{-\cfrac{2}{3}}x+6\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

so hmmm then we know the slope of that line is -2/3, so we're really looking for the point-slope form of a line with a slope of -2/3 and that passes through (-3 , 8)

(\stackrel{x_1}{-3}~,~\stackrel{y_1}{8})\hspace{10em} \stackrel{slope}{m} ~=~ -\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{8}=\stackrel{m}{-\cfrac{2}{3}}(x-\stackrel{x_1}{(-3)})\implies y-8=-\cfrac{2}{3}(x+3)

3 0
1 year ago
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