Answer is: 4,4 grams <span>of carbon dioxide gas would be produced.
</span>Chemical reaction: CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O.
m(CaCO₃) = 10 g.
n(CaCO₃) = 10 g ÷ 100 g/mol.
n(CaCO₃) = 0,1 mol.
From chemical reaction: n(CaCO₃) : n(CO₂) = 1 : 1.
n(CO₂) = 0,1 mol.
m(CO₂) = n(CO₂) · M(CO₂).
m(CO₂) = 0,1 mol· 44 g/mol.
m(CO₂) = 4,4 g.
Answer:
26.4960 is the answer for the first one
8.9569 is the answer for the second one
To calculate moles of any 
of a subtance, we need to divide the given mass by the molar mass of the substance that is 
given as per the question. By simply putting the values of the two masses we will be left with the number of moles of the given substance.
where, n= number of moles of given substance (mol)
m= given mass of the substance (grams)
M= molar mass of the given substance (grams/mol)
