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2 years ago

What impulse acts on a car that is slowly coming to a stop?

Physics

2 answers:

iragen [17]2 years ago

7 0

Answer:

When cars bounce off each other, or rebound, there is a larger change in momentum and therefore a larger impulse

Delicious77 [7]2 years ago

6 0

Answer:

Explanation:

When cars bounce off each other, or rebound, there is a larger change in momentum and therefore a larger impulse. A larger impulse means that a greater force is experienced by the occupants of the cars. When cars crumple together, there is a smaller change in momentum and therefore a smaller impulse.

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If opposing forces acting on an object are equal, the net force is

makkiz [27]

Answer:

0 N

Explanation:

suppose, you push a box with 5 N, and another person pushes the box on the opposite side of the box with 5 N, the net force (resultant ) is 0 N, the box will not move if it wasn't moving

hope this helps

8 0

3 years ago

Which conditions are low air pressure systems usually associated with?

Inga [223]

cloudy, wet weather

4 0

3 years ago

Read 2 more answers

Given uranium 235 go through an alpha, beta, beta, alpha, gamma, neutron and alpha. What do you have now?

Licemer1 [7]

Answer:

b. 88, 222

Explanation:

235U₉₂ ----→ Alpha --------→ 231P₉₀ ----→- beta -----→ 231Q₉₁ ------→-beta -------→231R₉₂--------→-alpha ------→-227S₉₀ ------→ gamma -----→-227S₉₀ ----------→ neutron ------→-226T₉₀-----------→ alpha --------→222 X ₈₈

Atomic No is 88 , atomic weight = 222 .

3 0

3 years ago

Light bulb 1 operates with a filament temperature of 3000 K, whereas light bulb 2 has a filament temperature of 2000 K. Both fil

MatroZZZ [7]

Answer:

A₁/A₂ = 0.44

Explanation:

The emissive power of the bulb is given by the formula:

P = σεAT⁴

where,

P = Emissive Power

σ = Stefan-Boltzman constant

ε = Emissivity

A = Surface Area

T = Absolute Temperature of Surface

FOR BULB 1:

Since, emissivity and emissive power are constant.

Therefore,

P = σεA₁T₁⁴ ----------- equation 1

where,

A₁ = Surface Area of Bulb 1

T₁ = Temperature of Bulb 1 = 3000 k

FOR BULB 2:

Since, emissivity and emissive power are constant.

Therefore,

P = σεA₂T₂⁴ ----------- equation 2

where,

A₂ = Surface Area of Bulb 2

T₂ = Temperature of Bulb 1 = 2000 k

Dividing equation 1 by equation 2, we get:

P/P = σεA₁T₁⁴/σεA₂T₂⁴

1 = A₁(3000)²/A₂(2000)²

A₁/A₂ = (2000)²/(3000)²

A₁/A₂ = 0.44

6 0

3 years ago

What is the most potentially destructive way to deal with stress while at college? a. texting friends back home b. watching TV c

diamong [38]

Answer:

Option (C)

Explanation:

Recreational drugs are usually referred to those drugs or medicines that are legally or illegally used without any prescription given by the doctors. These drugs include marijuana, cocaine, alcohol, nicotine, heroin, and many others. These drugs provide relaxation for a shorter period of time, but using of these substances, it makes an individual addicted to drugs.

So, recreational drugs are one of the most potentially destructive ways to handle stress when a student is in college.

Thus, the correct answer is option (C).

7 0

3 years ago