Question

9. A baseball pitcher hurls a 400 g baseball toward a batter with a speed of 30 m/s. The batter hits the pitch directly back toward the pitcher and it travels at 38 m/s. If the collision with the bat required 80 ms (milliseconds), find the force the bat applies to the ball. (Watch signs.)

Answer 1

Answer:

The force the bat applies to the ball is 340 N

Explanation:

given information:

mass of the ball, m = 400 g = 0.4 kg

initial velocity, $v_{i}$ = 30 m/s

final velocity, $v_{f}$  = 38 m/s

time, t = 80 ms = 0.08 s

the correlation between the change in momentum and the force is shown by the following equation

ΔP = FΔt

F = ΔP/Δt

where,

Δp = mΔv

     = m($v_{f} - v_{i}$)

     = m($v_{f} + v_{i}$)

$v_{i}$ = - because in opposite direction, thus

F = ΔP/Δt

  = m($v_{f} + v_{i}$)/Δt

   = (0.4)(38+30)/0.08

   = 340 N