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steposvetlana [31]
3 years ago
5

What does this picture represent?​

Chemistry
1 answer:
Shtirlitz [24]3 years ago
7 0

Answer:

idk buddy

don't know

Explanation:

I don't know

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A student decreases the temperature of a 556 c m cubed balloon from 278 K to 231 K. Assuming constant pressure, what should the
a_sh-v [17]

Answer:

The new volume of the balloon be 462\ cm^3.

Explanation:

We have,

Initial volume is 556 cm ³

The temperature of the balloon decreases from 278 K to 231 K.

We need to find the new volume of the balloon if the pressure is constant.

The Charles law states that at constant pressure, the volume of gas is directly proportional to its temperature i.e.

V\propto T, P is constant

\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}

V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{556\times 231}{278}\\\\V_2=462\ cm^3

So, the new volume of the balloon be 462\ cm^3.

3 0
3 years ago
Please answer he questions
Nastasia [14]

"Work done by a constant force on an object is the product of the force and the distance moved by the object in the direction of the force" -textbook

There is work done ONLY if the direction of the force and the direction the item is moving are the same. In figure A, the direction of the force (the lifting) is upwards (defying gravity), and the book is moving upwards, so work is done. In figure B, the force is still moving upwards (the person is carrying the books) but the book is moving to the right, so there is NO work done.

6 0
3 years ago
Which set of characteristics listed below are unique to the inner<br> planets?
Cerrena [4.2K]

Mercury,Mars,Venus,Earth

5 0
4 years ago
The specific heat of aluminum is 0.902 J/g C. If a one gram sample of aluminum absorbs 50 Joules of energy, how much with its te
PtichkaEL [24]
Answer:
55.4324℃
Explanation:
Q=cm△t
50J = 0.902J/(g·℃) x 1g x △t
△t =55.4324℃
7 0
3 years ago
A 1.900 g sample of C6H12 is burned in an excess of oxygen. What mass of C)2 and H20 should be obtained
Alexeev081 [22]
The balanced chemical reaction is:

<span>C6H12 + 9O2 = 6CO2 + 6H2O

We are given the amount of </span><span>C6H12 to be used for the reaction. THis will be the starting point for the calculations.

1.900 g </span>C6H12 ( 1 mol C6H12/ 84.18 g C6H12) ( 6 mol CO2 / 1 mol <span>C6H12) (44.01 g /mol ) = 5.96 g CO2
</span>1.900 g C6H12 ( 1 mol C6H12/ 84.18 g C6H12) ( 6 mol H2O / 1 mol <span>C6H12) (18.02 g /mol ) =  2.44 g H2O
</span>
6 0
3 years ago
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