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alina1380 [7]
3 years ago
15

What safety concerns must be addressed before

Engineering
1 answer:
Goryan [66]3 years ago
5 0

Answer:

the clothing you wear, what's in the air (gases), surrounding and weather

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A freshwater jet boat takes in water through side vents and ejects it through a nozzle of diameter D = 75 mm; the jet speed is V
Radda [10]

Answer:

a) 0.0663 m³/s

b) 3.312 N/(m/s)²

c) 16.665 m/s

d) 0.1105 m³/s

Explanation:

See attached pictures.

3 0
4 years ago
A 1000 W iron utilizes a resistance wire which is 20 inches long and has a diameter of 0.08 inches. Determine the rate of heat g
SSSSS [86.1K]

Answer:

The rate of heat generation in the wire per unit volume is 5.79×10^7 Btu/hrft^3

Heat flux is 9.67×10^7 Btu/hrft^2

Explanation:

Rate of heat generation = 1000 W = 1000/0.29307 = 3412.15 Btu/hr

Area (A) = πD^2/4

Diameter (D) = 0.08 inches = 0.08 in × 3.2808 ft/39.37 in = 0.0067 ft

A = 3.142×0.0067^2/4 = 3.53×10^-5 ft^2

Volume (V) = A × Length

L = 20 inches = 20 in × 3.2808 ft/39.37 in = 1.67 ft

V = 3.53×10^-5 × 1.67 = 5.8951×10^-5 ft^3

Rate of heat generation in the wire per unit volume = 3412.15 Btu/hr ÷ 5.8951×10^-5 ft^3 = 5.79×10^7 Btu/hrft^3

Heat flux = 3412.15 Btu/hr ÷ 3.53×10^-5 ft^2 = 9.67×10^7 Btu/hrft^2

3 0
3 years ago
Compute the number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m^
Nat2105 [25]

Answer:

The answer is "\bold{ 259.2 \times 10^{11} }".

Explanation:

The amount of kilograms, which travel in a thick sheet of hydrogen:

M= -DAt \frac{\Delta C}{ \Delta x} \\\\

D =1.0 \times 10^{8} \ \ \ \frac{m^2}{s} \\\\ A = 0.20 \ m^2\\\\t = 1\ \ h = 3600 \ \   sec \\\\

calculating the value of \Delta C:

\Delta C =C_A -C_B

  = 2.4 - 0.6 \\\\    = 1.8 \ \ \frac{kg}{m^3}

calculating the value of \Delta X:

\Delta x = x_{A} -x_{B}

     = 0 - (5\ mm) \\\\ = - 5 \ \ mm\\\\= - 5 \times 10^{-3} \ m

M = -(1.0 \times 10^{8}  \times 0.20 \times 3600 \times  (\frac{1.8}{-5 \times 10^{-3}})) \\\\

    = -(1.0 \times 10^{8}  \times 720 \times  (\frac{1.8}{-5 \times 10^{-3}})) \\\\= -(1.0 \times 10^{8}  \times \frac{ 1296}{-5 \times 10^{-3}})) \\\\= (1.0 \times 10^{8}  \times 259.2 \times 10^3)) \\\\= 259.2 \times 10^{11} \\\\

3 0
4 years ago
Differnence between boat and ship​
Blababa [14]

Answer:

a ship is a large vessel intended for oceangoing or at least deep-water transport, and a boat is anything else." Basically, a ship can carry a boat, but a boat cannot carry a ship

5 0
3 years ago
Read 2 more answers
A. Paleozoic
garri49 [273]
Pretty sure it’s Cenozoic
5 0
3 years ago
Read 2 more answers
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