One-dimensional, steady-state conduction with uniform internal energy generation occurs in a plane wall with a thickness of 50 m
1 answer:
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Answer:
Q=127.66W
L=9.2mm
Explanation:
Heat transfer consists of the propagation of energy in the form of heat in different ways, these can be convection if it is through a fluid, radiation through electromagnetic waves and conduction through solid solids.
To solve any problem related to heat transfer, the general equation is used
Q = delta / R
Where
Q = heat
Delta = the temperature difference
R = is the thermal resistance by conduction, convection and radiation
to solve this problem we propose the previous equation
Q = delta / R
later we find R
Q=(25-(-5))/0.235=127.66W
part b
we use the same ecuation with Q=127.66
Q = delta / R
Δ
Answer:
a)
b)
Explanation:
From the properties of Super-heated Refrigerant 134a Vapor at ,
; we obtain the following properties for specific enthalpy and specific entropy.
So; specific enthalpy
specific entropy
Also; from the properties of saturated Refrigerant 134 a vapor (liquid - vapor). pressure table at ; we obtain the following properties:
Given that the power input to the compressor is 2 hp;
Then converting to Btu/hr ;we known that since 1 hp = 2544.4342 Btu/hr
2 hp = 2 × 2544.4342 Btu/hr
2 hp = 5088.8684 Btu/hr
The steady state energy for a compressor can be expressed by the formula:
By neglecting kinetic and potential energy effects; we have:
b) To determine the entropy generation; we employ the formula:
In a steady state condition
Hence;