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galina1969 [7]
3 years ago
15

Acquisition of resources from an external source is called?

Engineering
1 answer:
densk [106]3 years ago
6 0

Answer:

subcontracting

Explanation:

I hope this is right

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Need help with these 3 ez questions pls help me.
vivado [14]

Answer:

21: False   22: Unprofessional behavior      23: True                                                      Explanation:

Hope this helps!

7 0
3 years ago
which of the following processes would be appropriate for cutting a narrow slot, less than 0.015 inch wide, in a 3/8- inch thick
Elena-2011 [213]

Laser beam machining and water jet cutting are the following processes would be appropriate for cutting a narrow slot, less than 0.015 inch wide, in a 3/8- inch thick sheet of fiber-reinforced plastic. Hence option d and f is correct.

<h3>What is fiber reinforced plastic?</h3>

Fiber reinforced plastic is defined as a polymer-based composite material that is strengthened by fiber support. Fiber-reinforced plastics (FRP) are composite materials that use glass or carbon fibers as reinforcement and polymer resins as a matrix.

Because laser cutting is a far less aggressive and abrasive process than water jet cutting, it is much more accurate. A laser can carefully and safely cut materials as thin as 0.006 inches, whereas water jet cutters can't handle cutting through surfaces smaller than 0.02 inches.

Thus, laser beam machining and water jet cutting are the following processes would be appropriate for cutting a narrow slot, less than 0.015 inch wide, in a 3/8- inch thick sheet of fiber-reinforced plastic. Hence option d and f is correct.

To learn more about fiber-reinforced plastic, refer to the link below:

brainly.com/question/11941367

#SPJ1

3 0
1 year ago
Solid Isomorphous alloys strength
Sphinxa [80]

Answer:

Explanation:

ℎ

3 0
3 years ago
Need help with both giving out brainlest for the people to help me
sammy [17]
The first one is d or the 4th answer choice and the second one is false. Hope this helps!
4 0
3 years ago
The velocity of a particle which moves along the s-axis is given by = 40 − 3 2/ , ℎ t is in seconds. Calculate the displacement
scoundrel [369]

The displacement ∆S of the particle during the interval from t = 2sec to 4sec is; 210 sec

<h3>How to find the displacement?</h3>

We are given the velocity equation as;

s' = 40 - 3t²

Thus, the speed equation will be gotten by integration of the velocity equation to get;

s = ∫40 - 3t²

s = 40t - ¹/₂t³

Thus, the displacement between times of t = 2 sec and t = 4 sec is;

∆S = [40(4) - ¹/₂(4)³] - [40(2) - ¹/₂(2)³]

∆S = 210 m

Read more about Displacement at; brainly.com/question/4931057

#SPJ1

8 0
2 years ago
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