Each side has to have at least 44 horses
F61160 N. This is further explained below.
<h3>What is the force?</h3>
Generally, We are only interested in the component that operates horizontally since the vertical components all cancel each other out. The pressure difference works on the hemisphere to generate a normal force all over the surface, but we are only concerned with that force's horizontal component. This may be determined by supposing the hemispheres to be two flat circular plates of the same radius as the hemispheres that have been forced together.
Therefore, force is equal to pressure multiplied by area, which is
F= (970 -15 )( * (0.45 m)2)
F=60754 N for each side.
Therefore, each side has to have at least 44 horses
44* 1390 = 61160 N
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According to newton's 3rd law of motion,
For every action, there is equal and opposite reaction. So if we move a body against a rough surface, there were be reaction against the force applied.
So using conservation of energy, we know:
Work done to move a body = Work done against Friction
So, Force applied * distance moved = coefficient of Friction * Normal Reaction * distance moved
For a body moving against a normal surface, Normal Reaction (R) = mg
or, mass * acceleration * distance (s) = ∪ * R * distance(s)
or, mass * (v^2/2s) = ∪ * mass * gravity
Now, s = stopping distance = v²/ 2∪g
so, using given value,∪=0.05,
s = v2/2*0.05*g
We know, g = 10, so s = v²/(2*0.05*10) = v²
where v = initial velocity
Answer:
Magnitude the net torque about its axis of rotation is 1.3338 Nm
Explanation:
The radius of the wrapped rope around the drum, r = 1.24 m
Force applied to the right side of the drum, F = 4.56 N
The radius of the rope wrapped around the core, r' = 0.57 m
Force on the cylinder in the downward direction, F' = 7.58 N
Now, the magnitude of the net torque is given by:
where
= Torque due to Force, F
= Torque due to Force, F'
Now,
The net torque comes out to be negative, this shows that rotation of cylinder is in the clockwise direction from its stationary position.
Now, the magnitude of the net torque:
Yes, that's a reasonable rounded value for the solution.
(5.7)² + (5.8)² = (32.49) + (33.64) = 66.13
√66.13 = 8.132...
= 8.1 when rounded to the nearest tenth.
The solution ' 8.1 ' is a reasonable rounded value, but only
if the question is changed to say 'km' at every place where
it now says 'km/hr'.
If 'km/hr' is correct, then there's no way to calculate Kiley's
effective northwesterly speed, using only the given information.
We don't know how long she traveled north at 5.7 km/hr,
and we don't know how long she traveled west at 5.8 km/hr.
So we don't know the distance between her start and end
points, and we don't know how long she traveled altogether ...
exactly the two numbers we need in order to calculate her
average speed. Or even, for that matter, the average direction
of her trip from start to finish.
Answer:
520 N
Explanation:
Work is the dot product of the force vector and displacement vector.
W = F · x
This means it is the product of the magnitudes of the vectors and the cosine of the angle between them.
W = F x cos θ
The displacement of the soil is 15 m up. The force is parallel to the ramp. So the angle between the vectors is 90° − 35° = 55°.
Plugging in the values and solving for F:
4500 J = F (15 m) (cos 55°)
F = 523 N
Rounded to two significant figures, the force is 520 N.
