1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ddd [48]
2 years ago
15

A cliff diver running 3.60 m/s dives out horizontally from the edge of a vertical cliff and reaches the water below 2.00 s later

. How
high is the cliff and how far from the base of the cliff did the diver hit the water?
Help asap
Physics
1 answer:
mart [117]2 years ago
8 0

Explanation:

It is given that,

The horizontal speed of a cliff diver, v_x=3.6\ m/s

It reaches the water below 2.00 s later, t = 2 s

Let d_x is the distance where the diver hit the water. It can be calculated as follows :

d_x=v_x\times t\\\\=3.6\times 2\\\\=7.2\ m

Let d_y is the height of the cliff. It can be calculated using second equation of motion as follows :

d_y=u_yt+\dfrac{1}{2}gt^2\\\\d_y=\dfrac{1}{2}\times 9.8\times 2^2\\\\=19.6\ m

So, the cliff is 19.6 m high and it will hit the water at a distance of 19.6 m.

You might be interested in
What objects has large volume and small mass
viva [34]

Answer:

A hot air balloon

7 0
3 years ago
How many seconds will it take for a satellite to travel 450,000 m at a rate of 120 m/s?
V125BC [204]
3750 seconds to travel that far
5 0
3 years ago
Please help me I am desperate this is due now
elena55 [62]

Answer:

Distance travelled is 7 meters and the displacement is 3 meters

7 0
2 years ago
Read 2 more answers
A boy pulls a 28.0-kg box with a 230-N force at 35° above a horizontal surface. If the coefficient of kinetic friction between t
ddd [48]

Answer:

1977.696 J

Explanation:

Given;

Weight of the box = 28.0 kg

Force applied by the boy = 230 N

angle between the horizontal and the force = 35°

Therefore,

the horizontal component of the force = 230 × cosθ

= 230 × cos 35°

= 188.405 N

Coefficient of kinetic friction, μ = 0.24

Force by friction, f = μN

here,

N = Normal force = Mass × acceleration due to gravity

or

N = 28 × 9.81 = 274.68 N

therefore,

f = 0.24 × 274.68

or

f = 65.9232 N

Now,

work done by the boy, W₁ = 188.405 N × Displacement  

= 188.405 N × 30

= 5652.15 J

and,

the

work done by the friction, W₂ = - 65.9232 N × Displacement  

= - 65.9232 N × 30 m

= - 1977.696 J

[ since the friction force acts opposite to the direction of motion, therefore the workdone will be negative]

8 0
3 years ago
Two trains are traveling side-by-side along parallel, straight tracks at the same speed. In a time t, train A doubles its speed.
sergij07 [2.7K]

Answer:

derdddrdickdd

Explanation:

3 0
3 years ago
Other questions:
  • Phase, color, and ductility are all examples of what type of property?
    7·1 answer
  • During a baseball game, a batter hits a high pop-up. If the ball remains in the air for 6.82 s, how high does it rise? The accel
    11·1 answer
  • What is the frequency of a photon with an energy of 1.99 x 10-19 j?
    14·1 answer
  • Under what condition is it possible for liquid water to have a higher temperature than water vapor when both are in the same con
    10·1 answer
  • What was so significant about dalton discoveries
    12·1 answer
  • Suppose the entire solar nebula had cooled to 50 K before the solar wind cleared the early solar system of its gases. How would
    13·1 answer
  • An oil layer that is 5.0 cm thick is spread smoothly and evenly over the surface of water on a windless day. A light ray from th
    8·1 answer
  • At what angle should the player aim the ball if it is thrown from a height of 8.5 ftft with a speed of 28 ft/sft/s?
    13·1 answer
  • The shape of the orbit for most comets is a(n):<br><br> circle<br> parabola<br> ellipse<br> oval
    13·1 answer
  • A scientist runs an electric current along a wire. A magnetic compass is placed near the wire. The scientist observes that whene
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!