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Studentka2010 [4]
3 years ago
8

For installations where the nonlinear load is huge, most consulting engineers will specify ____-rated transformers.

Engineering
1 answer:
Scorpion4ik [409]3 years ago
8 0

Answer:

K

Explanation:

For installations where the nonlinear load is huge, most consulting engineers will specify K-rated transformers.

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Sketch the velocity profile for laminar and turbulent flow.
Margarita [4]

Answer:

The laminar flow is generally given in high viscosity fluids such as honey or oil, it has the characteristic of flowing in an orderly manner, the walls of the tube have a zero speed while in the center it has a maximum speed.

turbulent flow is characterized by fluid velocity vectors presenting themselves in a disorderly manner and in all directions.

I attached the drawings for the velocity profile in laminar and turbulent flow.

4 0
3 years ago
Why are concrete masonry units (CMU) called breeze blocks?
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Answer:

A concrete masonry unit (CMU) is a standard-size rectangular block used in building construction. ... Those that use cinders (fly ash or bottom ash) as an aggregate material are called cinder blocks in the United States, breeze blocks (breeze is a synonym of ash) in the United Kingdom, and hollow blocks in the Philippines.

Explanation:

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3 years ago
Which of the following results from the fact that skip signals refracted from the ionosphere are elliptically polarized?
zhenek [66]

Answer:

B

Explanation:

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3 years ago
Legal metrology would protect consumers from businesses that do not take measurements according to defined measuring regulations
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4 years ago
A solid steel shaft has to transmit 100 kW at 160 RPM. Taking allowable shear stress at 70 Mpa, find the suitable diameter of th
MA_775_DIABLO [31]

Answer:

The diameter of the shaft is 80.5 mm.

Explanation:

Torsion equation is applied for the diameter of the solid shaft.

Step1

Given:

Power of the shaft is 100 kw.

Revolution per minute is 160 RPM.

Allowable shear stress is 70 Mpa.

Maximum torque is 20% more than the mean torque.  

Step2

Mean torque is calculated as follows:

P=T\omega

P=T(\frac{2\pi N}{60})

100\times 1000=T(\frac{2\pi 160}{60})

T=5968.31 N-m

Step3

Maximum torque is calculated as follows:

T_{max}=(1+\frac{20}{100})T

T_{max}=1.2T

T_{max}=1.2\times 5968.31

T_{max}=7161.97 N-m

Step4

Apply torsional equation for diameter of shaft as follows:

\tau _{max}=\frac{T_{max}}{\frac{\pi d^{3}}{16}}

70\times 10^{6}=\frac{7161.97}{\frac{\pi d^{3}}{16}}

d^{3}=5.211\times 10^{-4}

d=0.0805 m

or,

d=80.5 mm

Thus, the diameter of the shaft is 80.5 mm.

7 0
4 years ago
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