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Korolek [52]
3 years ago
5

Please help me with this. Picture

Engineering
1 answer:
qwelly [4]3 years ago
5 0

Answer:

^547.'":8765456\⇆⊇⊇ys p)(ay^547.'":8765456\⇆⊇⊇ys p)(*

iuytrT&*7654567iol;';";lk↓ωω*&65∴∀Hgtre

6и876&*b n™Ο65656&^cxCv876и876&*b n™‰‰ay^547.'":87765^&*  kIKUYtb

Explanation:

=yx^z3

ÜÜÜ

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Consider a pan of water being heated (a) by placing it on an electric range and (b) by placing a heating element in the water. W
Brrunno [24]

Answer:

Method B is the more efficient way of heating the water.

Explanation:

Method B is more efficient because by placing a heating element in the water as in described in method B, the heat that is lost to the surroundings is minimized which implies that more heat is supplied directly to the water. Therefore, more heating is achieved with a lesser amount of electrical energy input. Whereas placing the pan on a range means more heat losses to the surrounding and as such it will take a longer time for the water to heat up and also take more electrical energy.

7 0
3 years ago
Rose is building a circuit that accepts sound input and amplifies it. Which component will perform the amplification function?
PilotLPTM [1.2K]

Answer:

FET Transistor

Explanation:

A properly biased Field Effect Transistor will take the audio input and amplify it to drive speakers

8 0
3 years ago
A shaft machined of AISI 1022 steel having σuts = 70 ksi and σy = 52 ksi is loaded cyclically. The loading is characterized by t
Maru [420]

Answer:

2.075 in

Explanation:

Please kindly check attachment for the detailed and step by step solution of the given problem.

3 0
3 years ago
1. Nitrogen at an initial state of 300 K, 150 kPa, and 0.2 m3 is compressed slowly in an isothermal process to a final pressure
Sauron [17]

Answer:

Workdone during the process = 130kJ

Explanation:

Workdone by an expanding gas which is also called pressure-volume work, is defined as the pressure exerted by the gas molecules on the walls of the containing vessel. If work done by an expanding gas is the energy transferred to its surroundings i.e If volume increases, workdone is negative(loses energy).

In an isothermal process(constant Temperature of 300K, we use boyles law:

P1V1 = P2V2

V2 = (150 * 0.2)/800

= 0.0375 m3

W = -P(V2 - V1)

= 800*(0.0375 - 0.200)

= 130kJ

7 0
3 years ago
Suppose that the weights for newborn kittens are normally distributed with a mean of 125 grams and a standard deviation of 15 gr
kherson [118]

(a) If a kitten weighs 99 grams at birth, it is at 5.72 percentile of the weight distribution.

(b) For a kitten to be at 90th percentile, the minimum weight is 146.45 g.

<h3>Weight distribution of the kitten</h3>

In a normal distribution curve;

  • 2 standard deviation (2d) below the mean (M), (M - 2d) is at 2%
  • 1 standard deviation (d) below the mean (M), (M - d) is at 16 %
  • 1 standard deviation (d) above the mean (M), (M + d) is at 84%
  • 2 standard deviation (2d) above the mean (M), (M + 2d) is at 98%

M - 2d = 125 g - 2(15g) = 95 g

M - d = 125 g - 15 g = 110 g

95 g is at 2% and 110 g is at 16%

(16% - 2%) = 14%

(110 - 95) = 15 g

14% / 15g = 0.93%/g

From 95 g to 99 g:

99 g - 95 g  = 4 g

4g x 0.93%/g = 3.72%

99 g will be at:

(2% + 3.72%) = 5.72%

Thus, if a kitten weighs 99 grams at birth, it is at 5.72 percentile of the weight distribution.

<h3>Weight of the kitten in the 90th percentile</h3>

M + d = 125 + 15 = 140 g      (at 84%)

M + 2d = 125 + 2(15) = 155 g   ( at 98%)

155 g - 140 g = 15 g

14% / 15g = 0.93%/g

84% + x(0.93%/g) = 90%

84 + 0.93x = 90

0.93x = 6

x = 6.45 g

weight of a kitten in 90th percentile = 140 g + 6.45 g  = 146.45 g

Thus, for a kitten to be at 90th percentile, the approximate weight is 146.45 g

Learn more about standard deviation here: brainly.com/question/475676

#SPJ1

7 0
2 years ago
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