Ask question

Ask question

All categories

4 years ago

7

Determine the maximum intensity ww of the uniform distributed load that can be applied to the beam without risk of causing the s

trut to buckle.
Take F.S.F.S.x = 2.1 against buckling.

1 answer:

AnnyKZ [126]4 years ago

3 0

Answer:

Please see attachment

Explanation:

Please see attachment

You might be interested in

agasfer [191]

Answer: This is true.

Hope this helps! :)

Explanation:

4 0

3 years ago

A 35kg block of mass is subjected to forces F1=100N and F2=75N at agive angle thetha= 20° and 35° respectively.find the distance

Talja [164]

Answer:

21 m

Explanation:

Since F₁ = 100 N and acts at an angle of 20° to the horizontal, it has horizontal component F₁' = 100cos20° = 93.97 N and vertical component F₁" = 100sin20° = 34.2 N.

Also, F₂ = 75 N and acts at an angle of -35° to the horizontal, it has horizontal component F₂' = 75cos(-35°) = 75cos35° = 61.44 N and vertical component F₂" = 75sin(-35°) = -75sin35° = -43.02 N

The resultant horizontal force F₃' = F₁' + F₂' = 93.97 N + 61.44 N = 155.41 N

The resultant vertical force F₃" = F₁" + F₂" = 34.2 N - 43.02 N = -8.82 N

If f is the frictional force on the block, the net horizontal force on the block is F = F₃' - f.

Since f = μN where μ = coefficient of kinetic friction = 0.4 and N = normal force on the block.

For the block to be in contact with the surface, the vertical forces on the block must balance.

Since the normal force, N must equal the resultant vertical force F₃" and the weight, W = mg of the object for a zero net vertical force,

N = mg + F₃" (since both the weight and the resultant vertical force act downwards)

N = mg + F₃"

Since m = mass of block = 35 kg and g = acceleration due to gravity = 9.8 m/s² and F₃" = 8.82 N

So,

N = mg + F₃"

N = 35 kg × 9.8 m/s² + 8.82 N

N = 343 N + 8.82 N

N = 351.82 N

So, the net horizontal force F = F₃' - f.

F = 155.41 N - 0.4 × 351.82 N

F = 155.41 N - 140.728 N

F = 14.682 N

Since F = ma, where a = acceleration of block,

a = F/m = 14.682 N/35 kg = 0.42 m/s²

To find the distance the block moved, x we use the equation

x = ut + 1/2at² where u = initial speed of block = 0 m/s, t = time = 10 s and a = acceleration of block = 0.42 m/s²

Substituting the values of the variables into the equation, we have

x = ut + 1/2at²

x = 0 m/s × 10 s + 1/2 × 0.42 m/s² × (10 s)²

x = 0 m + 1/2 × 0.42 m/s² × 100 s²

x = 0.21 m/s² × 100 s²

x = 21 m

So, the distance moved by the block is 21 m.

4 0

3 years ago

What is matrix ? answer plzzz 27 point you got answer

HACTEHA [7]

Answer:

A matrix is a convenient and useful way of representing a graph to a computer. ... Matrices lend themselves easily to mechanical manipulations. Besides, many known results of matrix algebra can be readily applied to study the structural properties of graphs from an algebraic point of view.

4 0

3 years ago

Read 2 more answers

A 0.01 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender? select

Nataly_w [17]

Answer:

Option D

$H_o$ equals 0.5 $H_a$ less than 0.5

Explanation:

Information given

N=144

X=66

$P=\frac {x}{n}=66/144= 0.458333\approx 0.46$

The hypothesis

Null hypothesis

Probability, p =0.5

$H_o: p =0.5$

Alternative hypothesis

Probability, p<0.5

$H_a: p$

5 0

4 years ago

Propane gas C3H8 enters a combustion chamber operating at steady state condition at 1 bar, 25ºC and is burned with 150% theoreti

GalinKa [24]

Answer:

see explaination

Explanation:

Balanced equation or stoichiometry equation means in a product after reaction there is no unburned carbon compound left or we can say the oxygen is sufficient to combine with all the carbon and hydrogen moleculs to form Carbon-dioxide and water respectively.

The dew point temperature of balanced equation will be 100°c because water vapour bis present in it and it will condense at 100°c at 1 bar pressure while the other products need much lower temperatures to liquify.

See attachment.

6 0

4 years ago

Read 2 more answers