The thickness of aluminium needed to stop the beam electrons, protons and alpha particles at the given dfferent kinetic energies is 1.5 x 10⁻¹⁴ m.
<h3>
Thickness of the aluminum</h3>
The thickness of the aluminum can be determined using from distance of closest approach of the particle.
![K.E = \frac{2KZe^2}{r}](https://tex.z-dn.net/?f=K.E%20%3D%20%5Cfrac%7B2KZe%5E2%7D%7Br%7D)
where;
- Z is the atomic number of aluminium = 13
- e is charge
- r is distance of closest approach = thickness of aluminium
- k is Coulomb's constant = 9 x 10⁹ Nm²/C²
<h3>For 2.5 MeV electrons</h3>
![r = \frac{2KZe^2}{K.E} \\\\r = \frac{2 \times 9\times 10^9 \times 13\times (1.6\times 10^{-19})^2}{2.5 \times 10^6 \times 1.6 \times 10^{-19}} \\\\r = 1.5 \times 10^{-14} \ m](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7B2KZe%5E2%7D%7BK.E%7D%20%5C%5C%5C%5Cr%20%3D%20%5Cfrac%7B2%20%5Ctimes%209%5Ctimes%2010%5E9%20%5Ctimes%2013%5Ctimes%20%281.6%5Ctimes%2010%5E%7B-19%7D%29%5E2%7D%7B2.5%20%5Ctimes%2010%5E6%20%5Ctimes%201.6%20%5Ctimes%2010%5E%7B-19%7D%7D%20%5C%5C%5C%5Cr%20%3D%201.5%20%5Ctimes%2010%5E%7B-14%7D%20%5C%20m)
<h3>For 2.5 MeV protons</h3>
Since the magnitude of charge of electron and proton is the same, at equal kinetic energy, the thickness will be same. r = 1.5 x 10⁻¹⁴ m.
<h3>For 10 MeV alpha-particles</h3>
Charge of alpah particle = 2e
![r = \frac{2KZe^2}{K.E} \\\\r = \frac{2 \times 9\times 10^9 \times 13\times (2 \times 1.6\times 10^{-19})^2}{10 \times 10^6 \times 1.6 \times 10^{-19}} \\\\r = 1.5 \times 10^{-14} \ m](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7B2KZe%5E2%7D%7BK.E%7D%20%5C%5C%5C%5Cr%20%3D%20%5Cfrac%7B2%20%5Ctimes%209%5Ctimes%2010%5E9%20%5Ctimes%2013%5Ctimes%20%282%20%5Ctimes%201.6%5Ctimes%2010%5E%7B-19%7D%29%5E2%7D%7B10%20%5Ctimes%2010%5E6%20%5Ctimes%201.6%20%5Ctimes%2010%5E%7B-19%7D%7D%20%5C%5C%5C%5Cr%20%3D%201.5%20%5Ctimes%2010%5E%7B-14%7D%20%5C%20m)
Thus, the thickness of aluminium needed to stop the beam electrons, protons and alpha particles at the given dfferent kinetic energies is 1.5 x 10⁻¹⁴ m.
Learn more about closest distance of approach here: brainly.com/question/6426420
Answer:
no of unit is 17941
Explanation:
given data
fixed cost = $338,000
variable cost = $143 per unit
fixed cost = $1,244,000
variable cost = $92.50 per unit
solution
we consider here no of unit is = n
so here total cost of labor will be sum of fix and variable cost i.e
total cost of labor = $33800 + $143 n ..........1
and
total cost of capital intensive = $1,244,000 + $92.5 n ..........2
so here in both we prefer cost of capital if cost of capital intensive less than cost of labor
$1,244,000 + $92.5 n < $33800 + $143 n
solve we get
n > ![\frac{906000}{50.5}](https://tex.z-dn.net/?f=%5Cfrac%7B906000%7D%7B50.5%7D)
n > 17941
and
cost of producing less than selling cost so here
$1,244,000 + $92.5 n < 197 n
solve it we get
n >
n > 11904
so in both we get greatest no is 17941
so no of unit is 17941
Answer:
to power devices appliances and some methods of transportation
Explanation:
Answer:
B
Explanation:
This is a two sample t-test and not a matched pair t-test
null hypothesis(H0) will be that mean energy consumed by copper rotor motors is greater than or equal to mean energy consumed by aluminium rotor motors
alternate hypothesis(H1) will be that mean energy consumed by copper rotor motors is less than or equal to mean energy consumed by aluminium rotor motors.
So, option D is rejected
The hypothesis will not compare mean of differences of values of energy consumed by copper rotor motor and aluminium rotor motor.
Option A and C are also rejected