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katrin2010 [14]
2 years ago
5

Which features of figure JKLM remain the same after any rigid transformation? I-ready

Mathematics
1 answer:
Levart [38]2 years ago
8 0

Answer: size and shape

Step-by-step explanation:i got it right on the quiz

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Drag each length to the correct location on the image. Each length can be used more than once, but not all lengths will be used.
RSB [31]

Answer:

The length of the unknown sides of the triangles are as follows:

CD = 10√2

AC = 10√2

BC =  10

AB = 10

ΔACD is a right angle triangle. Therefore, Pythagoras theorem can be used to find the sides of the triangle.

c² = a² + b²

where

c = hypotenuse side = AD = 20

a and b are the other 2 legs

lets use trigonometric ratio to find CD,

cos 45 = adjacent / hypotenuse

cos 45 = CD / 20

CD = 1 / √2 × 20

CD = 20 / √2 = 20√2 / 2 = 10√2

20² - (10√2)² = AC²

400 - 100(2)  = AC²

AC² = 200

AC = √200 = 10√2

ΔABC is a right angle triangle too. Therefore,

AB² + BC² = AC²

Using trigonometric ratio,

cos 45 = BC / 10√2

BC = 10√2 × cos 45

BC = 10√2 × 1 / √2

BC = 10√2 / √2 =  10

(10√2)² - 10² = AB²

200 - 100 = AB²

AB² = 100

AB = 10

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Find the value of each variable.
Molodets [167]
There is no variables here
8 0
4 years ago
What is the formula for the expected number of successes in a binomial experiment with n trials and probability of success​ p? C
charle [14.2K]

Answer:

(D)E[ X ] =np.

Step-by-step explanation:

Given a binomial experiment with n trials and probability of success​ p,

f(x)=\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}, 0\leq  x\leq n

E(X)=\sum_{x=0}^{n}xf(x)= \sum_{x=0}^{n}x\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}

Since each term of the summation is multiplied by x, the value of the term corresponding to x = 0 will be 0. Therefore the expected value becomes:

E(X)=\sum_{x=1}^{n}x\left(\begin{array}{c}n\\x\end{array}\right)p^x(1-p)^{n-x}

Now,

x\left(\begin{array}{c}n\\x\end{array}\right)= \frac{xn!}{x!(n-x)!}=\frac{n!}{(x-)!(n-x)!}=\frac{n(n-1)!}{(x-1)!((n-1)-(x-1))!}=n\left(\begin{array}{c}n-1\\x-1\end{array}\right)

Substituting,

E(X)=\sum_{x=1}^{n}n\left(\begin{array}{c}n-1\\x-1\end{array}\right)p^x(1-p)^{n-x}

Factoring out the n and one p from the above expression:

E(X)=np\sum_{x=1}^{n}n\left(\begin{array}{c}n-1\\x-1\end{array}\right)p^{x-1}(1-p)^{(n-1)-(x-1)}

Representing k=x-1 in the above gives us:

E(X)=np\sum_{k=0}^{n}n\left(\begin{array}{c}n-1\\k\end{array}\right)p^{k}(1-p)^{(n-1)-k}

This can then be written by the Binomial Formula as:

E[ X ] = (np) (p +(1 - p))^{n -1 }= np.

5 0
4 years ago
Which of the following pairs of lines are perpendicular? Select all that apply
ad-work [718]
Perpendicular lines will have negative reciprocal slopes

B. y = -4x+ 5  and y = 1/4x + 4
D. y = x + 4 and y = -x + 4
E. y = -3 and x = -3

4 0
3 years ago
Find the area of a circle with radius, <br> r<br> = 6.43m.<br> Give your answer rounded to 2 DP.
Vesna [10]

Answer:

129.89 m²

Step-by-step explanation:

Area of a circle of radius r is A = πr².

If r = 6.43 m, then A = π(6.43 m)²  =  129.89 m²

5 0
3 years ago
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