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3241004551 [841]
2 years ago
11

The system brings molecules to the cells. It includes blood vessels and the heart.

Chemistry
1 answer:
makkiz [27]2 years ago
3 0
I think it’s the circulatory system. it delivers oxygen and nutrients to the cells and pumps blood to the heart. hope this helps:)
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What’s the difference between heterogeneous and homogeneous mixtures?
Ronch [10]

Answer:

Mixtures can be either homogeneous or heterogeneous. A mixture in which its constituents are distributed uniformly is called homogeneous mixture, such as salt in water. A mixture in which its constituents are not distributed uniformly is called heterogeneous mixture, such as sand in water.

5 0
2 years ago
3) How many moles of solute are dissolved in 1.5 L of a 0.80 M solution? * 10 points
Mrrafil [7]

Answer:

1.2

Explanation:

Molarity = moles/volume

to find the moles, you must multiply both sides by volume

so, take 1.5 L * 0.80 M

this equals 1.2 :)

7 0
2 years ago
If a buffer solution is 0.190 m in a weak acid (ka = 8.2 × 10-5) and 0.590 m in its conjugate base, what is the ph?\
Lubov Fominskaja [6]
<span>You use the Henderson - Hasselbalch equation pH = pKa + log ([salt]/[acid]) pKa = -log (8.2*10^-5) = 4.081 pH = 4.081 + (0.590/0.190) pH = 4.081 + log 3.105 pH = 4.081 + 0.49206 pH = 4.573</span>
5 0
2 years ago
Linoleic acid is a polyunsaturated fatty acid found, in ester form, in many fats and oils. Its doubly allylic hydrogens are part
Ganezh [65]

Answer:

Explanation:

Linoleic acid, which is polyunsaturated fatty acid, found

the three resonance structures are given as,

8 0
3 years ago
A 1.450 g sample of an unknown organic compound , X, is dissolved in 15.0 g of toluene
muminat

Answer:

Molecular weight of the compound = 372.13 g/mol

Explanation:

Depression in freezing point is related with molality of the solution as:

\Delta T_f = K_f \times m

Where,

\Delta T_f = Depression in freezing point

K_f = Molal depression constant

m = Molality

\Delta T_f = K_f \times m

1.33 = 5.12 \times m

m = 0.26

Molality = \frac{Moles\ of\ solute}{Mass\ of\ solvent\ in\ kg}

Mass of solvent (toluene) = 15.0 g = 0.015 kg

0.26 = \frac{Mole\ of\ compound}{0.015}

Moles of compound = 0.015 × 0.26 = 0.00389 mol

Mol = \frac{Mass\ in\ g}{Molecular\ weight}

Mass of the compound = 1.450 g

Molecular\ weight = \frac{Mass\ in\ g}{Moles}

Molecular weight = \frac{1.450}{0.00389} = 372.13\ g/mol

4 0
2 years ago
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