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3 years ago

Atoms of elements in the same group have the same number of . This is why they have similar chemical properties.

Chemistry

2 answers:

andrew11 [14]3 years ago

9 0

Answer: its , valence electrons I just did it

Dennis_Churaev [7]3 years ago

4 0

Answer:

Same number of electrons in their outer shell.

Explanation:

Whe working out their electronic configuration ( by looking at the atomic number) , one will find out that the number of electrons in their outer shell is also the same so the elements have to lose or gain the same amount of electrons to become stable.

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How many atoms are in Sodium, Carbon, Hydrogen, Oxygen, Fluorine, Boron, Lithium, Helium, Phosphorus and Sulfur?

vlada-n [284]

Sodium. 11
Carbon. 12
Hydrogen 1
Oxygen 2
Fluuorine. 14
Boron. 5
Lithium. 6
Helium 3
Phosphorus 15
Sulfur 6

6 0

3 years ago

I need help with this!

san4es73 [151]

Answer:

2.68 cm^3

Explanation:

Density= Mass/Volume

so...

8.96 g/cm^3 = 24.01 g/ V

and then u solve so it would be 2.68 cm ^3

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3 0

3 years ago

Which data can be measure quantitavtively

Marianna [84]

Quantitative data is a type of data that can be measured using numbers or is dealt with objectively. These include various types of data like temperature, weight, length, prices, area, volume, etc. now these data can be measured quantitatively.

sorry if i'm wrong

i'm new to brainly

7 0

2 years ago

Read 2 more answers

When HBr is added to pure water, HBr molecules lose protons, while water molecules gain protons. In this reaction, HBr is a(n)

Stells [14]

Acid Sorry if I am wrong but I am pretty positive it’s acid

3 0

2 years ago

A tank of gas is found to exert 8.6 atm at 38°C. What would be the required

Vesna [10]

Answer:

36.2 K

Explanation:

Step 1: Given data

Initial pressure of the gas (P₁): 8.6 atm

Initial temperature of the gas (T₁): 38°C

Final pressure of the gas (P₂): 1.0 atm (standard pressure)

Final temperature of the gas (T₂): ?

Step 2: Convert T₁ to Kelvin

We will use the following expression.

K = °C +273.15

K = 38 °C +273.15 = 311 K

Step 3: Calculate T₂

We will use Gay Lussac's law.

P₁/T₁ = P₂/T₂

T₂ = P₂ × T₁/P₁

T₂ = 1.0 atm × 311 K/8.6 atm = 36.2 K

6 0

2 years ago