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Nana76 [90]
3 years ago
12

61.2 grams of hydrogen sulfide react with 64.0 grams of Sulfur dioxide and produce 62.2 grams of solid sulfur (S8). (a) What amo

unt of solid sulfur do you expect to be produced, theoretically, by the reaction with the given quantities of reactants? (Limiting reagent problem
Will mark brainliest ​
Chemistry
2 answers:
ElenaW [278]3 years ago
7 0
Yes Because he really needs it. The amount of sulfur would be
tamaranim1 [39]3 years ago
6 0

Reaction

8SO₂ + 16H₂S → 3S₈ + 16H₂O

find limiting reactant

mol SO₂ = 64 : 64 g/mol =  1

mol H₂S = 61.2 : 34 g/mol = 1.8

ratio mol:coefficient

SO₂= 1 : 8= 0.125

H₂S=1.8 : 16 = 0.113

H₂S as a limiting reactant (smaller ratio)

mol S₈ will be based on limiting reactant (H₂S)

mol S₈ = 3/16 x 1.8 = 0.3375

mass S₈ = 0.3375 x 256 = 86.4 g

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podryga [215]

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3 years ago
Balance the following equation __N2+__O2→__N2O​
kakasveta [241]

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4 0
3 years ago
Can someone help me?
Oduvanchick [21]

Answer:

<u>an element with a large number of valence electrons and a large atomic radius</u>

Explanation:

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» If an atom has many valency electrons [ <em>empty</em><em> </em><em>orbitals</em><em> </em><em>i</em><em>n</em><em> </em><em>o</em><em>u</em><em>t</em><em>e</em><em>r</em><em>m</em><em>o</em><em>s</em><em>t</em><em> </em><em>s</em><em>h</em><em>e</em><em>l</em><em>l</em><em> </em>], it has difficulty in attracting electrons hence electronegativity low.

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7 0
3 years ago
Please help me with this question
Leviafan [203]

1. The resulting concentration will be 0.00044 mol/L

2. The minimum mass of sodium sulfite to add will be 0.4032 grams.

<h3>Stoichiometric problems</h3>

1. Using m1v1=m2v2

  m1 = 0.01 mol/L, v1 = 20 mL, v2 = 450 mL

 

       m2 = m1v1/v2 = 0.01 x 20/450 = 0.00044 mol/L

2. Na_2SO_3 + Ca(NO_3)_2 --- > 2NaNO_3 + CaSO_3

Mole ratio of the reactants = 1:1

Mole of 80 mL, 0.0400 mol/L Ca(NO3)2 = 80/1000 x 0.0400 = 0.0032 mol

Equivalent mole of Na2SO3 = 0.0032 moles

Mass of 0.0032 moles Na2SO3 = 0.0032 x 126 = 0.4032 grams

Thus, the minimum mass of sodium sulfite to be added must be 0.4032 grams.

More on stoichiometric calculations can be found here: brainly.com/question/27287858

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