Depression in freezing point (Δ
![T_{f}](https://tex.z-dn.net/?f=%20T_%7Bf%7D%20)
) =
![K_{f}](https://tex.z-dn.net/?f=%20K_%7Bf%7D%20)
×m×i,
where,
![K_{f}](https://tex.z-dn.net/?f=%20K_%7Bf%7D%20)
= cryoscopic constant =
![1.86^{0} C/m](https://tex.z-dn.net/?f=%201.86%5E%7B0%7D%20C%2Fm)
,
m= molality of solution = 0.0085 m
i = van't Hoff factor = 2 (For
![NaNO_{3}](https://tex.z-dn.net/?f=%20NaNO_%7B3%7D%20)
)
Thus, (Δ
![T_{f}](https://tex.z-dn.net/?f=%20T_%7Bf%7D%20)
) = 1.86 X 0.0085 X 2 =
![0.03162^{0}C](https://tex.z-dn.net/?f=%200.03162%5E%7B0%7DC%20)
Now, (Δ
![T_{f}](https://tex.z-dn.net/?f=%20T_%7Bf%7D%20)
) =
![T^{0}](https://tex.z-dn.net/?f=%20T%5E%7B0%7D%20)
- T
Here, T = freezing point of solution
![T^{0}](https://tex.z-dn.net/?f=%20T%5E%7B0%7D%20)
= freezing point of solvent =
![0^{0}C](https://tex.z-dn.net/?f=%200%5E%7B0%7DC%20)
Thus, T =
![T^{0}](https://tex.z-dn.net/?f=%20T%5E%7B0%7D%20)
- (Δ
![T_{f}](https://tex.z-dn.net/?f=%20T_%7Bf%7D%20)
) = -
Answer:
2 NO (g) → N2 (g) + O2 (g)
2 NOCl (g) → 2 NO (g) + Cl2 (g)
____________________________
2NOCl (g) ⟶ N2 (g) + O2 (g) + Cl2 (g)
ΔH = [90.3 kJ x 2 x -1] + [-38.6 kJ x -1 x 2] = -103.4 kJ
The ΔH for the reaction is -103.4 kJ
Answer:
Increasing the temperature increases reaction rates because of the disproportionately large increase in the number of high energy collisions. It is only these collisions (possessing at least the activation energy for the reaction) which result in a reaction.
Explanation: