Question

Consider the quadratic equation below.

Answer 1

Answer:

$x=\dfrac{-(-15)\pm\sqrt{(-15)^2-4(-2)(-3)} }{2(-2)}$

Step-by-step explanation:

Given equation:  $-2x^2 - 11x + 7 = 10 + 4x$

First, rearrange the equation so that it is in the general form of $ax^2+bx+c=0$

$-2x^2 - 11x + 7 = 10 + 4x$

Subtract 4x from both sides:

$-2x^2 - 15x + 7 = 10$

Subtract 10 from both sides:

$-2x^2 - 15x - 3 = 0$

Therefore,

• $a=-2$
• $b=-15$
• $c=-3$

Input these values into the quadratic formula:

$x=\dfrac{-b\pm\sqrt{b^2-4ac} }{2a}$

Therefore,

$x=\dfrac{-(-15)\pm\sqrt{(-15)^2-4(-2)(-3)} }{2(-2)}$

Answer 2

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