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arlik [135]
2 years ago
11

Consider the quadratic equation below.

Mathematics
2 answers:
Salsk061 [2.6K]2 years ago
8 0

Answer:

x=\dfrac{-(-15)\pm\sqrt{(-15)^2-4(-2)(-3)} }{2(-2)}

Step-by-step explanation:

Given equation:  -2x^2 - 11x + 7 = 10 + 4x

First, rearrange the equation so that it is in the general form of ax^2+bx+c=0

-2x^2 - 11x + 7 = 10 + 4x

Subtract 4x from both sides:

-2x^2 - 15x + 7 = 10

Subtract 10 from both sides:

-2x^2 - 15x - 3 = 0

Therefore,

  • a=-2
  • b=-15
  • c=-3

Input these values into the quadratic formula:

x=\dfrac{-b\pm\sqrt{b^2-4ac} }{2a}

Therefore,

x=\dfrac{-(-15)\pm\sqrt{(-15)^2-4(-2)(-3)} }{2(-2)}

alina1380 [7]2 years ago
6 0
Pls mark me as the Brainliest as I really need it!
Hope It Helps

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Infinitely many solutions means that you have the same thing on both sides of the equation no matter what value of x you plug in, right?

We just need both sides to be 3x then, correct?

If a were equal to 3 and b were equal to 0, we'd have

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Which is essentially 3x = 3x

So that means a = 3 and b = 0 must work!
Let's say x = 5

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miskamm [114]

Answer:

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Y-intercept : (0 , 2.5)

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When looking at the intersection on the y-axis, the x-coordinate will be 0. And when looking at the intersection on the x-axis, the y-coordinate will be 0.

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John borrows $6.50 from his friends to pay for snacks, and $11.75 from his sister to go to the movies how much money does he nee
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John has borrowed $6.50 from his friends and $11.75 from his sister. To find how much money he needs to repay you can just add up the amount of money he has borrowed.

Make an equation to solve for this, where x = amount of money John needs to repay. Make the amount of money John borrowed add up to x. Your equation should look like:

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Combine like terms (add 6.50 and 11.75).

$18.25 = x

After solving the equation, you have figured out that John need to repay $18.25 in total.

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Hola Amigos De Brainly les quiero pedir de su ayuda para resolver esta actividad El tema es ecuaciones cuadráticas y necesito que me ayuden POR FAVOR.

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