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stira [4]
2 years ago
7

In what ways will the addition of earth worms most likely affect the terrarium?

Chemistry
2 answers:
Gre4nikov [31]2 years ago
4 0

Answer: The soil biota benefits soil productivity and contributes to the sustainable function of all ecosystems. The cycling of nutrients is a critical function that is essential to life on earth. Earthworms (EWs) are a major component of soil fauna communities in most ecosystems and comprise a large proportion of macrofauna biomass. Their activity is beneficial because it can enhance soil nutrient cycling through the rapid incorporation of detritus into mineral soils. In addition to this mixing effect, mucus production associated with water excretion in earthworm guts also enhances the activity of other beneficial soil microorganisms. This is followed by the production of organic matter. So, in the short term, a more significant effect is the concentration of large quantities of nutrients (N, P, K, and Ca) that are easily assimilable by plants in fresh cast depositions. In addition, earthworms seem to accelerate the mineralization as well as the turnover of soil organic matter. Earthworms are known also to increase nitrogen mineralization, through direct and indirect effects on the microbial community. The increased transfer of organic C and N into soil aggregates indicates the potential for earthworms to facilitate soil organic matter stabilization and accumulation in agricultural systems, and that their influence depends greatly on differences in land management practices. This paper summarises information on published data on the described subjects.

Explanation: Protection of the soil habitat is the first step towards sustainable management of its biological properties that determine long-term quality and productivity. It is generally accepted that soil biota benefits soil productivity but very little is known about the organisms that live in the soil and the functioning of the soil ecosystem. The role of earthworms (EWs) in soil fertility is known since 1881, when Darwin (1809–1882) published his last scientific book entitled “The formation of vegetable mould through the action of worms with observations on their habits.’’ Since then, several studies have been undertaken to highlight the soil organisms contribution to the sustainable function of all ecosystems [1]. Soil macrofauna, such as EWs, modify the soil and litter environment indirectly by the accumulation of their biogenic structures (casts, pellets, galleries, etc.) (Table 1). The cycling of nutrients is a critical ecosystem function that is essential to life on earth. Studies in the recent years have shown increasing interest in the development of productive farming systems with a high efficiency of internal resource use and thus lower input requirement and cost [2, 3]. At present, there is increasing evidence that soil macroinvertebrates play a key role in SOM transformations and nutrient dynamics at different spatial and temporal scales through perturbation and the production of biogenic structures for the improvement of soil fertility and land productivity [4, 5]. EWs are a major component of soil fauna communities in most natural ecosystems of the humid tropics and comprise a large proportion of macrofauna biomass [6]. In cultivated tropical soils, where organic matter is frequently related to fertility and productivity, the communities of invertebrates—especially EWs—could play an important role in (SOM) dynamics by the regulation of the mineralization and humification processes [7–9]. The effects of EWs on soil biological processes and fertility level differ in ecological categories [12]. Anecic species build permanent burrows into the deep mineral layers of the soil; they drag organic matter from the soil surface into their burrows for food. Endogeic species live exclusively and build extensive nonpermanent burrows in the upper mineral layer of soil, mainly ingested mineral soil matter, and are known as “ecological engineers,’’ or “ecosystem engineers.’’ They produce physical structures through which they can modify the availability or accessibility of a resource for other organisms [13]. Epigeic species live on the soil surface, form no permanent burrows, and mainly ingest litter and humus, as well as on decaying organic matter, and do not mix organic and inorganic matter [14]. In the majority of habitats and ecosystems (Table 2), it is usually a combination of these ecological categories which together or individually are responsible for maintaining the fertility of soils [15–17]. EWs influence the supply of nutrients through their tissues but largely through their burrowing activities; they produce aggregates and pores (i.e., biostructures) in the

OleMash [197]2 years ago
3 0
Significantly modify the physical, chemical and biological properties of the soil profile.
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The atomic mass of the  magnesium is : 24.31⋅g.

<h3>What is isotopes?</h3>

Isotopes are members of a family of elements that all have the same number of protons and different numbers of neutrons. The number of protons in the nucleus determines the atomic number of an element on the periodic table.

Magnesium has three natural isotopes: ²⁴Mg, ²⁵Mg, and ²⁶Mg.

<h3>What is atomic mass ?</h3>

Atomic mass is the mass of an atom. The SI unit of mass is the kilogram, while atomic mass is often expressed in the non-SI unit dalton (synonymous with uniform atomic mass unit). 1 Da is defined as 1/12 the mass of a free carbon-12 atom at rest in the ground state.

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The atomic mass is the weighted average of the individual isotopic masses:

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4 0
1 year ago
A cubic box with sides of 20.0 cm contains 2.00 × 1023 molecules of helium with a root-mean-square speed (thermal speed) of 200
Anarel [89]

Answer:

1.133 kPa is the average pressure exerted by the molecules on the walls of the container.

Explanation:

Side of the cubic box = s = 20.0 cm

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V=(20.0 cm)^3=8000 cm^3=8\times 10^{-3} m^3

Root mean square speed of the of helium molecule : 200m/s

The formula used for root mean square speed is:

\mu=\sqrt{\frac{3kN_AT}{M}}

where,

= root mean square speed

k = Boltzmann’s constant = 1.38\times 10^{-23}J/K

T = temperature = 370 K

M = mass helium = 3.40\times 10^{-27}kg/mole

N_A = Avogadro’s number = 6.022\times 10^{23}mol^{-1}

T=\frac{\mu _{rms}^2\times M}{3kN_A}

Moles of helium gas = n

Number of helium molecules = N =2.00\times 10^{23}

N = N_A\times n

Ideal gas equation:

PV = nRT

Substitution of values of T and n from above :

PV=\frac{N}{N_A}\times R\times \frac{\mu _{rms}^2\times M}{3kN_A}

PV=\frac{N\times R\times \mu ^2\times M}{3k\times (N_A)^2}

R=k\times N_A

PV=\frac{N\times \mu ^2\times M}{3}

P=\frac{2.00\times 10^{23}\times (200 m/s)^2\times 3.40\times 10^{-27} kg/mol}{3\times 8\times 10^{-3} m^3}

P=1133.33 Pa =1.133 kPa

(1 Pa = 0.001 kPa)

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3 years ago
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4 years ago
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3 years ago
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Answer:

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Explanation:

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Reaction quotient (Q_{c}) for this reaction is represented as:

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4 years ago
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