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3 years ago

Which is TRUE of the products in this combustion reaction? 4Fe + 3O2 2Fe2O3

2 answers:

7 0

The only true answer is A.

products are on the right side of the reaction

products and reactants don't necessarily have same physical or chemical properties

It is the reactants that are the atoms, molecules, or compounds that participate in the reaction.

mote1985 [20]3 years ago

6 0

A. The products contain 4 iron atoms and 6 oxygen atoms. is the correct answer

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Which one is more metallic? A) Gold or B) Bismuth

Arlecino [84]

Answer:

Gold

Explanation:

Download pdf

6 0

3 years ago

Gasoline and motor oil are chemically similar. They are both mixtures of nonpolar hydrocarbons

Softa [21]

Answer:

motor oil

Explanation:

According to Oxford dictionary, viscosity refers to ''a quantity expressing the magnitude of internal friction in a fluid, as measured by the force per unit area resisting uniform flow.''

The higher the molecular weight of a substance, the greater its viscosity. This is because, the long chains in the viscous substance become entangled thereby increasing the internal friction in the liquid.

Motor oil is a heavier hydrocarbon than gasoline hence it is more viscous than gasoline.

5 0

3 years ago

Read 2 more answers

Draw the major organic product(s) for the reaction. The starting material is a benzene ring with one substituent. The substituen

Mice21 [21]

Answer:

See Explanation

Explanation:

In electrophilic aromatic substitution, the benzene ring undergoes substitution when it is reacted with suitable electrophiles.

The products of electrophilic aromatic substitution depends on the substituents already present on the benzene ring. Some substituents activate the ring towards electrophilic substitution and direct the incoming electrophile to the ortho and para positions on the ring while some substituents deactivate the benzene ring towards electrophilic substitution and direct the incoming electrophlle to the meta position on the ring.

The amide substituent is moderately activating and is an ortho, para director hence the products shown in the mage attached to this answer.

3 0

3 years ago

1‑Propanol ( P⁰ 1 = 20.9 Torr at 25 ⁰C ) and 2‑propanol ( P⁰ 2 = 45.2 Torr at 25 ⁰C ) form ideal solutions in all proportions. L

anastassius [24]

Answer : The mole fraction of vapor phase 1‑Propanol and 2‑Propanol is, 0.352 and 0.648 respectively.

Explanation : Given,

Vapor presume of 1‑Propanol $(P^o_1)$ = 20.9 torr

Vapor presume of 2‑Propanol $(P^o_2)$ = 45.2 torr

Mole fraction of 1‑Propanol $(x_1)$ = 0.540

Mole fraction of 2‑Propanol $(x_2)$ = 1-0.540 = 0.46

First we have to calculate the partial pressure of 1‑Propanol and 2‑Propanol.

$p_1=x_1\times p^o_1$

where,

$p_1$ = partial vapor pressure of 1‑Propanol

$p^o_1$ = vapor pressure of pure substance 1‑Propanol

$x_1$ = mole fraction of 1‑Propanol

$p_1=(0.540)\times (20.9torr)=11.3torr$

and,

$p_2=x_2\times p^o_2$

where,

$p_2$ = partial vapor pressure of 2‑Propanol

$p^o_2$ = vapor pressure of pure substance 2‑Propanol

$x_2$ = mole fraction of 2‑Propanol

$p_2=(0.46)\times (45.2torr)=20.8torr$

Thus, total pressure = 11.3 + 20.8 = 32.1 torr

Now we have to calculate the mole fraction of vapor phase 1‑Propanol and 2‑Propanol.

$\text{Mole fraction of 1-Propanol}=\frac{\text{Partial pressure of 1-Propanol}}{\text{Total pressure}}=\frac{11.3}{32.1}=0.352$

and,

$\text{Mole fraction of 2-Propanol}=\frac{\text{Partial pressure of 2-Propanol}}{\text{Total pressure}}=\frac{20.8}{32.1}=0.648$

Thus, the mole fraction of vapor phase 1‑Propanol and 2‑Propanol is, 0.352 and 0.648 respectively.

3 0

3 years ago

Carbon-14 is an isotope used in carbon dating. The nucleus becomes Nitrogen-14 through beta decay. Its half-life is 5370 years.

frosja888 [35]

Answer:

If the half-life of 14C is 5730 years, when this period of time has passed it will have been halved, it is called the exponential decay law of radioactive isotopes.

8 0

3 years ago