The overall rate law in terms of the initial rate of the reaction is:
= ![k_{overall} [H_{2} SO_{4} ]^{2} [C_{6}H_{6}]](https://tex.z-dn.net/?f=k_%7Boverall%7D%20%5BH_%7B2%7D%20SO_%7B4%7D%20%5D%5E%7B2%7D%20%5BC_%7B6%7DH_%7B6%7D%5D)
The Sulfonation of benzene has the following mechanism:
(1) 
⇌ 
[fast]
(2) 
→ 
[slow]
(3) 
→ 
[fast]
(4) 
→ 
[fast]
<h3>Calculation of rate law:</h3>
Given that the reaction's slowest step is the rate-dependent step, the following is the definition of rate law:
Rate = ![k_{2} [SO_{3} ][C_{6} H_{6} ]](https://tex.z-dn.net/?f=k_%7B2%7D%20%5BSO_%7B3%7D%20%5D%5BC_%7B6%7D%20H_%7B6%7D%20%5D)
However, the issue is that because 
is an intermediate, it cannot be accounted for in the general rate legislation.
The following rate rule governs the synthesis of :
Rate = ![k_{1}[H_{2} SO_{4} ]^{2}](https://tex.z-dn.net/?f=k_%7B1%7D%5BH_%7B2%7D%20SO_%7B4%7D%20%20%5D%5E%7B2%7D)
Consequently, if we replace equation 1 with equation 2,
Rate is determined to be =
Hence, the overall rate law in terms of the initial rate of the reaction is:
=
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Answer:
B
Explanation:
Chemistry is the study of matter, its composition and the changes it undergoes.
Answer:
5. Amplitude.
6. 344.8 meters/second
Explanation:
5. The energy is proportional to the amplitude is all I remember. Sorry :/ Been a long time since I took these classes.
6. Traveling to the wall & back is 200m
100 + 100 = 200m total traveled
The time is 0.58s so, we can use the speed formula to solve [ s = d/t ] where s = speed, d = distance, and t = time.
s = 200/0.58
s = 344.82758
I don’t know if they’ll have you round, but I would say the speed of the sound is 344.8 m/s.
Answer:
a. Theoretical yield = 8.81 g
b. 77 %
Explanation:
We begin from the reaction:
2Fe (s) + 3Cl₂ (g) → 2FeCl₃ (s)
and the excess is the iron, so the limiting reagent is the chlorine.
We convert mass to moles → 5.78 g / 70.90 g/mol = 0.0815 mol
Ratio is 3:2 so we think this:
From 3 moles of chlorine, I can produce 2 moles of Iron (III) chloride
Then 0.0815 moles would produce (0.0815 . 2) /3 = 0.0543 moles
This is the theoretical yield. We convert the moles to mass:
0.0543 mol . 162.2 g /mol = 8.81 g
If the reaction yields 6.79 g of FeCl₃ and the theoretical yield is 8.81 g ,we can obtain the percent yield: (6.79 / 8.81) . 100 = 77 %
Density = mass / volume
1.5 = m / 50.0
m = 1.5 x 50.0
m = 75 g
hope this helps!
