Answer is: the percent by mass of NaHCO₃ is 2,43%. m(NaHCO₃) = 10 g. V(H₂O) = 400 ml. d(H₂O) = 1 g/ml. m(H₂O) = V(H₂O) · d(H₂O). m(H₂O) = 400 ml · 1 g/ml. m(H₂O) = 400 g. m(solution) = m(H₂O) + m(NaHCO₃). m(solution) = 400 g + 10 g. m(solution) = 410 g. ω(NaHCO₃) = 10 g ÷ 410 g · 100%. ω(NaHCO₃) = 2,43 %