1.4406 × 10⁻⁶ is the Ka(dissociation constant) for the acid.
The equilibrium constant for the reaction of an acid with water is the acid dissociation constant, where the acid, HA separates into H⁺ and A⁻ ions.
The acid dissociation constant is represented by (Ka).
So let's first imagine that the given monoprotic acid is HA.
HA will dissociate into H⁺ and A⁻ ions.
HA ⇒ H⁺ and A⁻
The formula used for Ka is
Ka = [H⁺] [A⁻] / [HA]
Given
pH = 2.83
[HA] = 1.50 M
From the given pH, we can calculate [H⁺] and [A⁻]
[H⁺] = [A⁻] = 1 × = 1.47 × 10⁻³ M
Ka = 1.47 × 10⁻³ × 1.47 × 10⁻³ / 1.50
Ka = 1.4406 × 10⁻⁶
Hence, 1.4406 × 10⁻⁶ is the Ka for the acid.
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Answer: Hello your question is poorly written attached below is the complete question
answer:
450 kg
Explanation:
mass of product formed = mass of reactants that reacted
hence :
mass of compound C that can be formed and shipped
= mass of A + mass of B
= 200 kg + 250 kg = 450 kg ( theoretical mass of compound formed )
The answer that is most likely true about ocean temperatures surrounding Australia, which is marked by the star in the following map is that b) the ocean temperatures north of Australia are higher than the ocean temperatures south of Australia.
Answer:
224 grams of O₂
Explanation:
This is the reaction:
2 C₂H₆ (g) + 7 O₂(g) → 4 CO₂ (g) + 6 H₂O (g)
2 moles of ethene react with 7 moles of oxygen.
Let's convert the ethene's mass into moles (mass / molar mass)
60 g / 30 g/m = 2 mol
So, if 2 moles of ethene must react with 7 moles of O₂ and we have 2 moles, obviously we would need 7 moles of oyxgen.
Let's convert the moles to mass ( mol . molar mass)
7 m . 32 g/m = 224 grams