Answer:
Stars emit colors of many different wavelengths, but the wavelength of light where a star's emission is concentrated is related to the star's temperature - the hotter the star, the more blue it is; the cooler the star, the more red it is
Answer:
64.5 cm
Explanation:
30 * 80 + x * 110 = 50* 190 => x = 64.5
Answer:
![m=\rho\times \frac{4}{3} \times \pi \times(r_2^3-r_1^3 )](https://tex.z-dn.net/?f=m%3D%5Crho%5Ctimes%20%5Cfrac%7B4%7D%7B3%7D%20%5Ctimes%20%5Cpi%20%5Ctimes%28r_2%5E3-r_1%5E3%20%20%29)
Explanation:
- We have to make a hollow sphere of inner radius
and outer radius
.
Then the mass of the material required to make such a sphere would be calculated as:
Total volume of the spherical shell:
![V_t=\frac{4}{3} \pi.r_2^3](https://tex.z-dn.net/?f=V_t%3D%5Cfrac%7B4%7D%7B3%7D%20%5Cpi.r_2%5E3)
And the volume of the hollow space in the sphere:
![V_h=\frac{4}{3} \pi.r_1^3](https://tex.z-dn.net/?f=V_h%3D%5Cfrac%7B4%7D%7B3%7D%20%5Cpi.r_1%5E3)
Therefore the net volume of material required to make the sphere:
![V=V_t-V_h](https://tex.z-dn.net/?f=V%3DV_t-V_h)
![V=\frac{4}{3} \pi(r_2^3-r_1^3)](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B4%7D%7B3%7D%20%5Cpi%28r_2%5E3-r_1%5E3%29)
- Now let the density of the of the material be
.
<u>Then the mass of the material used is:</u>
![m=\rho.V](https://tex.z-dn.net/?f=m%3D%5Crho.V)
![m=\rho\times \frac{4}{3} \times \pi \times(r_2^3-r_1^3 )](https://tex.z-dn.net/?f=m%3D%5Crho%5Ctimes%20%5Cfrac%7B4%7D%7B3%7D%20%5Ctimes%20%5Cpi%20%5Ctimes%28r_2%5E3-r_1%5E3%20%20%29)