Answer:
A POSTAL PACKAGE IS PUSHED BY A HORIZONTAL TABLE WITH A FORCE F = 40N. PACKAGE MOVES ON A DISTANCE OF 1.5M WHICH MECHANICAL WORK PERFORMS THIS FORCE
PT TEST
Answer:
D. the linear velocity of the point of contact (relative to the inclined surface) is zero
Explanation:
The force of friction emerges only when there is relative velocity between two objects . In case of perfect rolling , there is no sliding so relative velocity between the surface and the point of contact is zero . In other words the velocity of point of contact becomes zero , even though , the whole body is in linear motion . It happens due point of contact having two velocities which are equal and opposite . One of the velocity is in forward direction and the other velocity which is due to rotation is in backward direction . So net velocity of point of contact becomes zero . Due to absence of sliding , displacement due to friction becomes zero . Hence work done by friction becomes zero.
Answer:The net force acting on the car is 3×103 Newtons
Explanation:
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Answer:
Option D
48 N
Explanation:
From Newton's law of motion we deduce that the magnitude of force is a product of mass and acceleration hence expressed as, F=ma where F is the magnitude of force, m is the mass of the object and a is the acceleration of the cart. Substituting 24 kg for m and 2 for acceleration then
F=24*2= 48 N