does anyone know the three answers Question 1 which element is in group 5 period 2?, question 3 which element is in group 6 peri
2 answers:
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Answer: 0.172 M
Explanation:
a) To calculate theconcentration of base, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is
are the n-factor, molarity and volume of base which is NaOH.
We are given:
Putting values in above equation, we get:
b) To calculate the concentration of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is
are the n-factor, molarity and volume of base which is NaOH.
We are given:
Putting values in above equation, we get:
The concentration of the phosphoric acid solution is 1.172 M
<u>Answer:</u> The mass of methanol that must be burned is 24.34 grams
<u>Explanation:</u>
We are given:
Amount of heat produced = 581 kJ
For the given chemical equation:
By Stoichiometry of the reaction:
When 764 kJ of heat is produced, the amount of methanol reacted is 1 mole
So, when 581 kJ of heat will be produced, the amount of methanol reacted will be =
To calculate mass for given number of moles, we use the equation:
Moles of methanol = 0.7605 moles
Molar mass of methanol = 32 g/mol
Putting values in above equation, we get:
Hence, the mass of methanol that must be burned is 24.34 grams
Explanation:
(a) The given data is as follows.
Load applied (P) = 1000 kg
Indentation produced (d) = 2.50 mm
BHI diameter (D) = 10 mm
Expression for Brinell Hardness is as follows.
HB =
Now, putting the given values into the above formula as follows.
HB = =
=
= 200
Therefore, the Brinell HArdness is 200.
(b) The given data is as follows.
Brinell Hardness = 300
Load (P) = 500 kg
BHI diameter (D) = 10 mm
Indentation produced (d) = ?
d =
=
= 4.46 mm
Hence, the diameter of an indentation to yield a hardness of 300 HB when a 500-kg load is used is 4.46 mm.