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2 years ago

Convert 3,526 meters (m) into kilometers (km). (Don't forget units) EN Voranean

Chemistry

1 answer:

Nina [5.8K]2 years ago

6 0

Answer:

3,526 meters (m) into kilometers (km) = 0.003526 kilometers

Explanation:

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kvv77 [185]

Answer:

I think it's B " Constraints are more important than criteria ".

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2 years ago

PLSS HELP! The gas carbon dioxide is a pure substance. Which of the following is true about carbon dioxide? (4 points)

Nadusha1986 [10]

Answer:

The answer is option A..

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2 years ago

A 20 g granite boulder absorbs 300.2 Joules of energy from the Sun, resulting in its temperature

s344n2d4d5 [400]

Answer:

19 °C

Explanation:

Step 1: Given and required data

Mass of granite (m): 20 g

Heat absorbed (Q): 300. 2 J

Specific heat capacity of granite (c): 0.790 J/g.°C

Step 2: Calculate the temperature change (ΔT)

We will use the following expression.

Q = c × m × ΔT

ΔT = Q/c × m

ΔT = 300.2 J/(0.790 J/g.°C) × 20 g = 19 °C

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2 years ago

Gaseous butane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 13. g of butane is m

12345 [234]

Answer: The maximum amount of water that could be produced by the chemical reaction is 20.16 grams

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For butane:

Given mass of butane = 13 g

Molar mass of butane = 58.12 g/mol

Putting values in equation 1, we get:

$\text{Moles of butane}=\frac{13g}{58.12g/mol}=0.224mol$

For oxygen gas:

Given mass of oxygen gas = 70.9 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

$\text{Moles of oxygen gas}=\frac{70.9g}{32g/mol}=2.216mol$

The chemical equation for the reaction of butane and oxygen gas follows:

$2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O$

By Stoichiometry of the reaction:

2 moles of butane reacts with 13 moles of oxygen gas

So, 0.224 moles of butane will react with = $\frac{13}{2}\times 0.224=1.456mol$ of oxygen gas

As, given amount of oxygen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, butane is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of butane produces 10 moles of water

So, 0.224 moles of butane will produce = $\frac{10}{2}\times 0.224=1.12moles$ of water

Now, calculating the mass of water from equation 1, we get:

Molar mass of water = 18 g/mol

Moles of water = 1.12 moles

Putting values in equation 1, we get:

$1.12mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=(1.12mol\times 18g/mol)=20.16g$

Hence, the maximum amount of water that could be produced by the chemical reaction is 20.16 grams

8 0

3 years ago

What is the compound name of S3I9?

klasskru [66]

Trisulfur nonaiodide

Step-by-step explanation:
The name for a binary molecular compound has the form
Multiplying prefix+name of first element multiplying prefix+stem of second element element+ide (two words)
The multiplying prefixes for three and nine are tri and nona, respectively.
The stem of iodine is iod.
Put them together, and the name of S₃I₉ is
trisulfur nonaiodide.

4 0

2 years ago

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