Question

Help please I need help with this

Answer 1

Answer:

  π/6 ≈ 11/21 cubic units

Step-by-step explanation:

Use the given values in the formula for the volume of a sphere:

  V = 4/3πr³

  V = (4/3)(22/7)(1/2)³ = 4·22/(3·7·8) = 11/21 . . . . cubic units

Answer 2

We know,

${\qquad { \longrightarrow \pmb {\sf Volume_{(Sphere)} = \dfrac{4}{3} \pi {r}^{3} }}}$

Here,

• Radius of the sphere is $\sf\dfrac{1}{2} .$

• We will take the value of π as $\sf\dfrac{22}{7} .$

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Substituting the values in the formula :

${ \longrightarrow {\qquad {\sf Volume_{(Sphere)} = \dfrac{4}{3} \times \dfrac{22}{7} \times {\bigg(\dfrac{1}{2} \bigg)}^{3} }}}$

${ \longrightarrow {\qquad {\sf Volume_{(Sphere)} = \dfrac{4}{3} \times \dfrac{22}{7} \times \dfrac{1}{8} }}}$

${ \longrightarrow {\qquad {\sf Volume_{(Sphere)} = \dfrac{ \cancel4}{3} \times \dfrac{22}{7} \times \dfrac{1}{ \cancel8} }}}$

${ \longrightarrow {\qquad {\sf Volume_{(Sphere)} = \dfrac{ 1}{3} \times \dfrac{22}{7} \times \dfrac{1}{ 2} }}}$

${ \longrightarrow {\qquad {\sf Volume_{(Sphere)} = \dfrac{22}{3 \times 7 \times 2} }}}$

${ \longrightarrow {\qquad {\sf Volume_{(Sphere)} = \dfrac{22}{42} }}}$

${ \longrightarrow {\qquad {\bf Volume_{(Sphere)} = \dfrac{11}{21} }}}$

⠀

Therefore,

• Radius of the sphere is $\bf \dfrac{11}{21}$ units³.