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Leto [7]
3 years ago
14

The box plots show the average wind speeds, in miles per hour, for various cities in two different countries.

Mathematics
1 answer:
Delvig [45]3 years ago
3 0

Answer:

B.) The data in country B are more symmetric than the data in country A.

Step-by-step explanation:

mark me brainliest!!

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4x^2-25=39<br> Solve for x
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Answer:

u can find the answer in calculate

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Carter and his family are driving from Atlanta to Raleigh. They drive for 2 hours and 45 minutes at an average speed of 60 miles
Blizzard [7]
Driving for 2 hours and 45 minutes at an average speed of 60 miles per hour.
2 hours and 45 minutes = 2 hours and 45 minutes 0r 2.75 hrs                                                                  _________                                                                  60minutes
D = rt = 60mph *2.75hr = 165mi 

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3 years ago
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Consider these functions f(x)=3x-7 g(x)=x+1/x-1 what is the of f(g(3)) answer
JulijaS [17]

Answer:

\boxed{-1}

.

Step-by-step explanation:

g(3) = \frac{3 + 1}{3 - 1}  = 2

f(g(3)) = 3(2) - 7 = -1

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3 years ago
While making oatmeal cookies, Angela needs to add 1/2 cup of milk to her dough. However, she has only a 1/4-cup measuring cup. H
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The number of times she has to fill it up is 2 times
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A store is having a sale on chocolate chips and walnuts. For 3 pounds of chocolate chips and 5 pounds of walnuts, the total cost
umka21 [38]

c = cost per pound of chocolate chips

w = cost per pound of walnuts.

\bf \stackrel{\textit{3 lbs of "c"}}{3c}+\stackrel{\textit{5 lbs of "w"}}{5w}~~=~~\stackrel{\textit{costs}}{15} \\\\\\ \stackrel{\textit{12 lbs of "c"}}{12c}+\stackrel{\textit{2 lbs of "w"}}{2w}~~=~~\stackrel{\textit{costs}}{33} \end{cases}\qquad \impliedby \textit{let's use elimination} \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{llccccccl} 3c+5w=15&\times (-4)\implies &-12c&+&-20w&=&-60\\ 12c+2w=33&&12c&+&2w&=&33\\ \cline{3-7}\\ &&0&&-18w&=&-27 \end{array}

\bf -18w=-27\implies w=\cfrac{-27}{-18}\implies \blacktriangleright w=\cfrac{3}{2} \blacktriangleleft \\\\\\ \stackrel{\textit{substituting on the 1st equation}}{3c+5\left(\cfrac{3}{2} \right)=15}\implies 3c+\cfrac{15}{2}=15 \implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{2}}{2\left( 3c+\cfrac{15}{2} \right)=2(15)} \\\\\\ 6c+15=30\implies 6c=15\implies c=\cfrac{15}{6}\implies \blacktriangleright c=\cfrac{5}{2} \blacktriangleleft

6 0
4 years ago
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