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morpeh [17]
2 years ago
11

This question is about magnetisation. I will give brainliest!!

Physics
1 answer:
FromTheMoon [43]2 years ago
6 0

Answer:

By seeing by how far away can it attract a paperclip.

Explanation:

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When this pendulum swings, at which point is its kinetic energy the<br> highest? *
Eddi Din [679]

Answer:

The bottom/center of the pendulum

Explanation:

As it swings, the pendulum will have maximum potential energy at the top of its arc.

As it comes back towards the center that potential energy will convert into kinetic energy until it reaches the middle of its swing (when the pendulum is fully vertical) where all potential energy has been converted into kinetic energy.

This is when the kinetic energy is the highest

As it begins to move away from the center of its arc, that kinetic energy will convert into potential energy again, and the process repeats

5 0
3 years ago
A ray diagram without the produced image is shown.
Mashutka [201]
The answer is real and smaller than the object. The image point of the top of the object is the point where the two refracted rays intersect. Tracing the entire image having the same distance from the mirror as the image of the top of the object and with the bottom on the principal axis. Hence, a real inverted image will be formed for an object outside the focal point. 
3 0
3 years ago
Read 2 more answers
True or False: Any wavelength of light would work for this experiment. Explain your response, including the term quantum or quan
emmainna [20.7K]

Answer:

I think false I don't know if I right but I hoped this help

6 0
3 years ago
Un hamster fait tourner sa cage de 27cm de diamètre a raison de 14tours par minute .quel est le module de l accélération centrip
Scilla [17]

Answer:

Explanation:

a_c = ω²R

14 rev/min (2π rad/rev)(1 min/60 s) = 1.466 rad/s

a_c = 1.466²(0.27/2)

a_c = 0.29 m/s²

Le hamster est lent

6 0
3 years ago
A 40.0 kg box is placed on a 2.00 m tall shelf. If the box falls off the shelf, what is its kinetic energy as it strikes the gro
RUDIKE [14]
M = 40 Kg , g=9.8 m/s² , h = 2 m

PE = m g h

PE = (40) (9.8) (2)

PE = 784 J

KE = PE

½m v² = m g h

½ v² = g h

½ v² = (9.8) (2)

½ v² = 19.6

v² = 19.6×2

v² = 39.2

V = √39.2

V = 6.26 m/s

KE = ½mv²

KE = ½(40) (6.26)²

KE =783.8 J
6 0
3 years ago
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