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1 year ago

Four students measured the acceleration of gravity. The accepted value for

1 answer:

7 0

Answer: The student with the largest measurement of percentage error is student 4. Option A is correct.The percent error shows the disparity between the observed value and the actual value. It is given by the expression.

Therefore, we can conclude that the student's measurement that has the largest percent error is student 4.

Explanation:

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A playground merry-go-round has a mass of 115 kg and a radius of 2.50 m and it is rotating with an angular velocity of 0.520 rev

tatuchka [14]

Answer:

$W_f = 2.319 rad/s$

Explanation:

For answer this we will use the law of the conservation of the angular momentum.

$L_i = L_f$

so:

$I_mW_m = I_sW_f$

where $I_m$ is the moment of inertia of the merry-go-round, $W_m$ is the initial angular velocity of the merry-go-round, $I_s$ is the moment of inertia of the merry-go-round and the child together and $W_f$ is the final angular velocity.

First, we will find the moment of inertia of the merry-go-round using:

I = $\frac{1}{2}M_mR^2$

I = $\frac{1}{2}(115 kg)(2.5m)^2$

I = 359.375 kg*m^2

Where $M_m$ is the mass and R is the radio of the merry-go-round

Second, we will change the initial angular velocity to rad/s as:

W = 0.520*2 $\pi$ rad/s

W = 3.2672 rad/s

Third, we will find the moment of inertia of both after the collision:

$I_s = \frac{1}{2}M_mR^2+mR^2$

$I_s = \frac{1}{2}(115kg)(2.5m)^2+(23.5kg)(2.5m)^2$

$I_s = 506.25kg*m^2$

Finally we replace all the data:

$(359.375)(3.2672) = (506.25)W_f$

Solving for $W_f$ :

$W_f = 2.319 rad/s$

7 0

2 years ago

Plz help!!!!! Due tomorrow Analyze the weather map in 2 to 3 complete sentences. Describe what the weather will be in Olympia, W

lana66690 [7]

Answer:

Very sorry if this is late

Explanation:

Currently, in Olympia, Washington, it is raining because a cold front with high pressure has met an area with low pressure. This occurs due to the fact that storms are caused by sudden differences in air pressure.

8 0

2 years ago

A golf ball reaches a height of 150 m before it stops rising and starts to fall to the ground. What is the golf balls speed (rou

artcher [175]

Answer:

v = 54 m/s

Explanation:

Given,

The maximum height of the flight of golf ball, h = 150 m

The velocity at height h, u = 0

The velocity of the golf ball right before it hits the ground, v = ?

Using the III equations of motion