Ask question

Ask question

All categories

3 years ago

15

How is the direction of a vector affected when it is multiplied by a scalar?

1 answer:

pantera1 [17]3 years ago

6 0

The direction of a vector multiplied by a scalar is only affected if the scalar is negative, in which case the vector will now be in the opposite direction. If the scalar is positive, the vector will only change in magnitude

You might be interested in

How do you calculate the magnitude of the resultant force of two

zlopas [31]

Answer:

Two forces that act in opposite directions produce a resultant force that is smaller than either individual force. To find the resultant force subtract the magnitude of the smaller force from the magnitude of the larger force. The direction of the resultant force is in the same direction as the larger force.

3 0

3 years ago

Read 2 more answers

I have two of these so if you think this is easy then another free ten points in my profile!

Agata [3.3K]

Answer:

z

Explanation:

x repersents a new moon and the others repersent quarter moons

(x is a new moon because new moons are often the phase when the moon is close to earths sun)

7 0

3 years ago

Read 2 more answers

Add me and ill add you back!! you have to bc i just gave you free coins :)

Rainbow [258]

Answer:

yoooooooooooooooooooo

Explanation:

6 0

3 years ago

Read 2 more answers

True or False: Exercise is an underrated stress reliever and can be used to 25

Andreyy89

Answer:

I think it is true I'm not saying it is but if you get another person who says its true say true

Explanation:

5 0

3 years ago

Read 2 more answers

To practice Problem-Solving Strategy 17.1 for wave interference problems. Two loudspeakers are placed side by side a distance d

Nimfa-mama [501]

Complete Question

The compete question is shown on the first uploaded question

Answer:

The speed is $v = 350 \ m/s$

Explanation:

From the question we are told that

The distance of separation is d = 4.00 m

The distance of the listener to the center between the speakers is I = 5.00 m

The change in the distance of the speaker is by $k = 60 cm = 0.6 \ m$

The frequency of both speakers is $f = 700 \ Hz$

Generally the distance of the listener to the first speaker is mathematically represented as

$L_1 = \sqrt{l^2 + [\frac{d}{2} ]^2}$

$L_1 = \sqrt{5^2 + [\frac{4}{2} ]^2}$

$L_1 = 5.39 \ m$

Generally the distance of the listener to second speaker at its new position is

$L_2 = \sqrt{l^2 + [\frac{d}{2} ]^2 + k}$

$L_2 = \sqrt{5^2 + [\frac{4}{2} ]^2 + 0.6}$

$L_2 = 5.64 \ m$

Generally the path difference between the speakers is mathematically represented as

$pD = L_2 - L_1 = \frac{n * \lambda}{2}$

Here $\lambda$ is the wavelength which is mathematically represented as

$\lambda = \frac{v}{f}$

=> $L_2 - L_1 = \frac{n * \frac{v}{f}}{2}$

=> $L_2 - L_1 = \frac{n * v}{2f}$

=> $L_2 - L_1 = \frac{n * v}{2f}$

Here n is the order of the maxima with value of n = 1 this because we are considering two adjacent waves

=> $5.64 - 5.39 = \frac{1 * v}{2*700}$

=> $v = 350 \ m/s$

7 0

3 years ago