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dolphi86 [110]
2 years ago
9

A solid steel ball is thrown directly downward, with an initial speed 7.30 m/s, from the top of a building at a height of 29.5 m

. How much time in seconds does it take before the ground?
​
Physics
2 answers:
Flura [38]2 years ago
5 0

Answer:

1.82 seconds

Explanation:

see paper for full explanation :)

lara31 [8.8K]2 years ago
4 0

h=vi.t+1/2gt²

29.5 = 7.3t+1/2 x 9.8 x t²

4.9t²+7.3t-29.5=0

abc formula⇒ t = 1.82 s

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First of all, I is proportional V according to the Ohm's Law. R is merely a constant you need to obtain an equation. However, it is true that R changes with temperature and pressure, therefore Ohm's Law is only applicable in an invariable environment. Also this constant R is different for different materials.

So, do not get confused.

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3 years ago
Object A has a mass of 5 kg and a velocity of 6 m/s to the east while Object 1 point B has a mass of 12 kg and velocity 0.6 m/s
Olin [163]

Answer:

Momentum of system = 37.2 Kgm/s.

Explanation:

<u>Given the following data;</u>

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  • Velocity A = 6 m/s
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  • Velocity B = 0.6 m/s

To find the momentum of the system;

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

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<u>For object B;</u>

Momentum B = 12 * 0.6

Momentum B = 7.2 Kgm/s

Next, we would determine the momentum of this system using the formula;

Momentum of system = Momentum A + Momentum B

Substituting the values into the formula, we have;

Momentum of system = 30 + 7.2

<em>Momentum of system = 37.2 Kgm/s.</em>

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4 0
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vova2212 [387]

Answer:

See below

Explanation:

Energy is lost in the form of friction/heat/sound

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5 0
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