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baherus [9]
3 years ago
15

Object A has a mass of 5 kg and a velocity of 6 m/s to the east while Object 1 point B has a mass of 12 kg and velocity 0.6 m/s

also to the east. What is the momentum of the system? (Let east be positive)
help plss I got family
Physics
1 answer:
Olin [163]3 years ago
8 0

Answer:

Momentum of system = 37.2 Kgm/s.

Explanation:

<u>Given the following data;</u>

  • Mass A = 5 kg
  • Velocity A = 6 m/s
  • Mass B = 12 kg
  • Velocity B = 0.6 m/s

To find the momentum of the system;

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

Momentum = mass * velocity

<u>For object A;</u>

Momentum A = 5 * 6

Momentum A = 30 Kgm/s

<u>For object B;</u>

Momentum B = 12 * 0.6

Momentum B = 7.2 Kgm/s

Next, we would determine the momentum of this system using the formula;

Momentum of system = Momentum A + Momentum B

Substituting the values into the formula, we have;

Momentum of system = 30 + 7.2

<em>Momentum of system = 37.2 Kgm/s.</em>

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A 70-kg boy is surfing and catches a wave which gives him an initial speed of 1.6 m/s. He then drops through a height of 1.60 m,
Tems11 [23]

Answer:

3.6 KJ

Explanation: Given that a 70-kg boy is surfing and catches a wave which gives him an initial speed of 1.6 m/s. He then drops through a height of 1.60 m, and ends with a speed of 8.5 m/s. How much nonconservative work (in kJ) was done on the boy

The workdone = the energy.

There are two different energies in the scenario - the potential energy (P.E ) and the kinetic energy ( K.E )

P.E = mgh

P.E = 70 × 9.8 × 1.6

P.E = 1097.6 J

P.E = 1.098 KJ

K.E = 1/2mv^2

K.E = 1/2 × 70 × 8.5^2

K.E = 2528.75 J

K.E = 2.529 KJ

The non conservative workdone = K.E + P.E

Work done = 1.098 + 2.529

Work done = 3.63 KJ

Therefore, the non conservative workdone is 3.6 KJ approximately

5 0
3 years ago
The speed of a boat in still water is 20 mph. it travels from one pier to another with the current in 4 hours and back against t
saw5 [17]
The answer is, "the speed of the current is 5 miles per hour."

To calculate the speed of the current,
let's assume speed of current =  xmph. Time taken to travel from one pier to another with the current = 100/(20+x)h


But the time taken to travel from one pier to another with the current, which is given is = 4 hours. So,  4=100/(20+x) 80+4x = 100

4x = 20

x = 5 Thus, the speed of the current is 5 miles per hour.
3 0
3 years ago
During an earthquake, where is the greatest motion felt on the surface?
dalvyx [7]
That would be the epicenter. 
5 0
3 years ago
In the decreasing order of magnitude, which of the following is correct?
Sergio [31]

Answer:

b. Static > sliding > rolling friction.

Explanation:

Static friction is greater than sliding friction.  It takes more force to get an object to start sliding than to keep it sliding.

Sliding friction is greater than rolling friction.  There are fewer points of contact for a round surface compared to a flat one.

5 0
4 years ago
A parcel is traveling on a horizontal conveyer belt moving at 1 meter/second. At the end of the conveyor belt, the parcel lands
Igoryamba

Assume the acceleration due to gravity is approximately 9.8 m/s^2


In 1 second, it will fall


s = ut + at^2/2


u = initial vertical velocity = 0

a = 9.8

t = 1


s is the distance it falls

= 9.8/2 = 4.9 m


But the parcel has a horizontal velocity of 1 m/s so it will travel 1 m horizontally in 1 second.


The answer would be

1 metre, 4.9 metres.



6 0
3 years ago
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