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baherus [9]
3 years ago
15

Object A has a mass of 5 kg and a velocity of 6 m/s to the east while Object 1 point B has a mass of 12 kg and velocity 0.6 m/s

also to the east. What is the momentum of the system? (Let east be positive)
help plss I got family
Physics
1 answer:
Olin [163]3 years ago
8 0

Answer:

Momentum of system = 37.2 Kgm/s.

Explanation:

<u>Given the following data;</u>

  • Mass A = 5 kg
  • Velocity A = 6 m/s
  • Mass B = 12 kg
  • Velocity B = 0.6 m/s

To find the momentum of the system;

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

Momentum = mass * velocity

<u>For object A;</u>

Momentum A = 5 * 6

Momentum A = 30 Kgm/s

<u>For object B;</u>

Momentum B = 12 * 0.6

Momentum B = 7.2 Kgm/s

Next, we would determine the momentum of this system using the formula;

Momentum of system = Momentum A + Momentum B

Substituting the values into the formula, we have;

Momentum of system = 30 + 7.2

<em>Momentum of system = 37.2 Kgm/s.</em>

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Can anyone help with this?
sleet_krkn [62]

Answer:

A. The volume of the object

Explanation:

First of all, it can only PROBABLY be A or D

But why is it only A?

  • Mass = The amount of matter in an object (nothing related here)
  • Volume = How much space is the object taking (super related here)

It's VOLUME here and not MASS here because:

  • It it would be Mass, then the object size could be anything, but the liquid wouldn't move as much higher.
  • But because it is Volume, it is taking space, which makes the liquid move
  • If the Mass would be the answer, then it would be totally not related, because mass isn't related over here, it matters about size.

<h2>Hence, A. The volume of the object </h2>

is your answer!!!!

4 0
2 years ago
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(3) A Ninja motorcycle is moving down I95 at 160 miles per hour (72 m/s) and a cop uses a radar gun to measure the speed. Using
Virty [35]

Answer:

it does use it at doppler

Explanation:

My dad told me the hes a cop so yw

5 0
3 years ago
At the local playground, a 21-kg child sits on the right end of a horizontal teeter-totter, 1.8 m from the pivot point. On the l
Ksju [112]

Answer:

By convention a negative torque leads to clockwise rotation and a positive torque leads to counterclockwise rotation.

here weight of the child =21kgx9.8m/s2 = 205.8N

the torque exerted by the child Tc = - (1.8)(205.8) = -370.44N-m ,negative sign is inserted because this torque is clockwise and is therefore negative by convention.

torque exerted by adult Ta = 3(151) = 453N , counterclockwise torque.

net torque Tnet = -370.44+453 =82.56N , which is positive means counterclockwise rotation.

b) Ta = 2.5x151 = 377.5N-m

Tnet = -370.44+377.5 = 7.06N-m , positive ,counterclockwise rotation.

c)Ta = 2x151 = 302N-m

Tnet = -370.44+302 = -68.44N-m, negative,clockwise rotation.

5 0
3 years ago
The normal force acting on an object and the force of static friction do zero work on the object. However the reason that the wo
spin [16.1K]

Answer:

<em>The normal force is perpendicular to the displacement</em>

<em>The static friction force produces no displacement</em>

Explanation:

Work Done By Special Forces

The work is a physical magnitude that measures the dot product of the force applied to an object by the displacement it produces in it.

W=\vec F\ \vec r

It can be written in its scalar version as

W=F.d.cos\theta

Being F and d the magnitudes of the force and displacement, and \theta the angle between them

If the angle is zero, the work is at maximum, it the angle is 90°, the work is zero. If the angle is between 90° and 180°, the work is negative.

The normal force acts in the vertical direction when the object is being pushed horizontally. It means the angle between the force and the displacement is 90°, thus the work is

W=N.d.cos90^o=0

The work is zero because the force and the displacement are perpendicular

The static friction force exists only when the object is being applied a force of a magnitude not large enough to produce movement, i.e. the object is at rest. If the object is moved, the friction force is still present, but it's called dynamic friction force, usually smaller than the static.

Since in this case, there is no displacement, d=0, and the work is

W=F_r(0)cos180^o=0

3 0
4 years ago
What is the term used for sediments building up at the mouth of the river? (Hint: think New Orleans)
meriva
I believe it’s called Alluvium! It’s where the river mouth is build up of gravel,sand,silt, and clay!!
4 0
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