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bija089 [108]
2 years ago
12

A container of N, 03(9) has a pressure of 0.490 atm. When the absolute temperature of the N, O2(g) is tripled, the gas

Chemistry
1 answer:
spayn [35]2 years ago
3 0

Answer: 1.59atm

Explanation:

We have that for the Question "Calculate the final pressure of the gas mixture, assuming that the container volume does not change."

it can be said that

The final pressure of the gas mixture, assuming that the container volume does not change =

From the question we are told

A container of N2O3(g) has a pressure of 0.265 atm. When the absolute temperature of the N2O3(g) is tripled, the gas completely decomposes, producing NO2(g) and NO(g).

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A proton travels at a speed of 2.0 × 106 meters/second. Its velocity is at right angles with a magnetic field of strength 5.5 ×
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So here we are given that the the velocity of the proton ( V ) is 2.0 × 10^6 meters / second, with a magnetic field of strength 5.5 × 10^{-3}  tesla. If they each form a right angle, they are hence perpendicular to one another, such that ....

F = q( V × B ),

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.... they form the following formula. Let's go through each of the variables in our formula here -

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All we have to do now is plug and chug,

F = ( 1.602 × 10^{19} )( 2.0 × 10^6 )( 5.5 × 10^{-3} ) = ( About ) 1.8 × 10^{-15} Newtons

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Mercury has a density of 13.6 grams/mL, what is this density in cg/L?
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