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bija089 [108]
2 years ago
12

A container of N, 03(9) has a pressure of 0.490 atm. When the absolute temperature of the N, O2(g) is tripled, the gas

Chemistry
1 answer:
spayn [35]2 years ago
3 0

Answer: 1.59atm

Explanation:

We have that for the Question "Calculate the final pressure of the gas mixture, assuming that the container volume does not change."

it can be said that

The final pressure of the gas mixture, assuming that the container volume does not change =

From the question we are told

A container of N2O3(g) has a pressure of 0.265 atm. When the absolute temperature of the N2O3(g) is tripled, the gas completely decomposes, producing NO2(g) and NO(g).

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A 1.59 mol sample of Kr has a volume of 641 mL. How many moles of Kr are in a 4.41 L sample at the same temperature and pressure
Marina86 [1]

Answer:

The correct answer is 10.939 mol ≅ 10.94 mol

Explanation:

According to Avogadro's gases law, the number of moles of an ideal gas (n) at constant pressure and temperature, is directly proportional to the volume (V).

For the initial gas (1), we have:

n₁= 1.59 mol

V₁= 641 mL= 0.641 L

For the final gas (2), we have:

V₂: 4.41 L

The relation between 1 and 2 is given by:

n₁/V₁ = n₂/V₂

We calculate n₂ as follows:

n₂= (n₁/V₁) x V₂ = (1.59 mol/0.641 L) x 4.41 L = 10.939 mol ≅ 10.94 mol

5 0
2 years ago
Is this the correct answer?
Alona [7]
I believe so, looks like it
8 0
3 years ago
How many atoms are in 1.0 formula units of magnesium acetate?
Ray Of Light [21]

Answer:

15

Explanation:

Magnesium Acetate Mg(C2H3O2)2

Number of atoms:

Carbon = 4

Hydrogen = 6

Magnesium = 1

Oxygen = 4

Total = 15

7 0
3 years ago
A sample of O2 with an initial temperature of 50.0 oC and a volume of 105 L is cooled to -25 oC. The new pressure is 105.4 kPa a
Damm [24]

Answer:

71.92 kPa

Explanation:

Using the combined gas law equation;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (kPa)

P2 = final pressure (kPa)

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question;

T1 = 50°C = 50 + 273 = 323K

V1 = 105L

T2 = -25°C = -25 + 273 = 248K

P2 = 105.4 kPa

P1 = ?

V2 = 55.0 L

Using P1V1/T1 = P2V2/T2

P1 × 105/323 = 105.4 × 55/248

105P1/323 = 5797/248

0.325P1 = 23.375

P1 = 23.375 ÷ 0.325

P1 = 71.92 kPa

4 0
3 years ago
Please answer. Brainliest!
vichka [17]

Answer:

the equation is unbalanced

5 0
3 years ago
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