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3 years ago

State any two effects of gravitational force

Physics

1 answer:

CaHeK987 [17]3 years ago

4 0

Answer:

The effect of gravity extends from each object out into space in all directions, and for an infinite distance. However, the strength of the gravitational force reduces quickly with distance. Humans are never aware of the Sun's gravity pulling them because the pull is so small at the distance between the Earth and Sun.

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What do the vertical columns in the periodic table indicate?

romanna [79]

The correct answer is

D. Groups and Families

I did the quiz nd this was the right answer

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3 years ago

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Calculate the length of a simple pendulum that oscillates with a frequency of 0.4Hz g=10m/s2 , ^=3.142

earnstyle [38]

Answer:

Explanation:

For simple pendulum the formula is

$T=2\pi\sqrt{\frac{l}{g} }$

Where T is time period , l is length and g is acceleration due to gravity .

$\frac{1}{n} =2\pi\sqrt{\frac{l}{g} }$

n is frequency

Putting the values

$\frac{1}{.4} =2\pi\sqrt{\frac{l}{10} }$

$\frac{l}{10} = .1584$

l = 1.584 m

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3 years ago

A force of 20 N is executed to raise a rock weighing 30 N. What is the actual mechanical advantage?

xxMikexx [17]

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3 years ago

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The quantity of charge Q in coulombs (C) that has passed through a point in a wire up to time t (measured in seconds) is given b

Mnenie [13.5K]

Explanation:

The quantity of charge Q in coulombs (C) that has passed through a point in a wire up to time t (measured in seconds) is given by :

$Q=t^3-2t^2+4t+4$

We need to find the current flowing. We know that the rate of change of electric charge is called electric current. It is given by :

$I=\dfrac{dQ}{dt}\\\\I=\dfrac{d(t^3-2t^2+4t+4)}{dt}\\\\I=3t^2-4t+4$

At t = 1 s,

Current,

$I=3(1)^2-4(1)+4\\\\I=3\ A$

So, the current at t = 1 s is 3 A.

For lowest current,

$\dfrac{dI}{dt}=0\\\\\dfrac{d(3t^2-4t+4)}{dt}=0\\\\6t-4=0\\\\t=0.67\ s$

Hence, this is the required solution.

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3 years ago

A packet is dropped from a stationary helicopter, hovering at a height 'h' from the ground level, reaches the ground in 12s. Cal

Ksju [112]

Use kinematic equations to solve:

1) yf = yo + vo*t + 1/2at²

yf = final height
yo = initial height
vo = initial velocity
a = acceleration
t = time

yf - yo = vo*t + 1/2at²

yf - yo = h

vo = 0

Thus,

h = 1/2at²

h = 1/2(9.8)(12)² = 705.6 m

2) vf = vo + at

vo = 0

Thus,

vf = at

vf = (9.8)(12) = 117.6 m/s

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3 years ago

State any two effects of gravitational force ​

State any two effects of gravitational force