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mafiozo [28]
2 years ago
13

Calculate the solubility of Hg2Cl2 given that its ksp is 1.1*10^-18?

Chemistry
1 answer:
Evgen [1.6K]2 years ago
8 0
At 25°C, the solubility product of Hg2Cl2 in water is 3.2
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antiseptic1488 [7]

Answer: 1. AgF + CaCl2 = AgCl + CaF2

2. C2H4 +O2 = CO2 +H2O

3. K2S = K+S

4. O2 + Mg = MgO

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6.C2H6O + O2= CO2 + H2O

7.Li2SO4 + MgCl2= Li2SO4 + MgCl2

8.HCl + Zn= H2 + ZnCl2

Explanation:

Balance the equation

Write down your given equation.

Write down the number of atoms per each element that you have on each side of the equation.

Always leave hydrogen and oxygen for last.

If you have more than one element left to balance:

Add a coefficient to the single carbon atom on the right of the equation to balance it with the 3 carbon atoms on the left of the equation.

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4 0
3 years ago
When sound molecules "stack up" in front of high-speed flights, what could
FrozenT [24]

pretty sure its B thank me later

4 0
3 years ago
PLEASE HELP!!!!!
aivan3 [116]

Answer:

During the process of reaching thermal equilibrium heat is transferred between the object. heat is always transferred from the object at the higher temperature to the object with lower temperature. For a gas, the heat transfer is related to a change in temperature.

5 0
3 years ago
Which is a postulate of the kinetic molecular theory of gases? Despite being very small, the volume occupied by the individual p
Paladinen [302]

Answer:

The particles that compose a gas are so small compared to the distances between them that the volume of the individual particles can be assumed to be negligible.  

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7 0
3 years ago
Read 2 more answers
Calculate the energy required to heat 566.0mg of graphite from 5.2°C to 23.2°C. Assume the specific heat capacity of graphite un
maw [93]

Answer:

7.23 J

Explanation:

Step 1: Given data

  • Mass of graphite (m): 566.0 mg
  • Initial temperature: 5.2 °C
  • Final temperature: 23.2 °C
  • Specific heat capacity of graphite (c): 0.710J·g⁻¹K⁻¹

Step 2: Calculate the energy required (Q)

We will use the following expression.

Q = c × m × ΔT

Q = 0.710J·g⁻¹K⁻¹ × 0.5660 g × (23.2°C-5.2°C)

Q = 7.23 J

6 0
3 years ago
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