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mafiozo [28]
2 years ago
13

Calculate the solubility of Hg2Cl2 given that its ksp is 1.1*10^-18?

Chemistry
1 answer:
Evgen [1.6K]2 years ago
8 0
At 25°C, the solubility product of Hg2Cl2 in water is 3.2
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How would a flood be a limitation for synthetic polymers that rely on natural rubber in its production?
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A flood, if it hits the environment of the natural rubbers, would destroy how the rubber is being produced. to have a large amount of limitation, the flood would destroy a large percentage of rubber trees. This natural rubber is needed to make synthetic polymers. Without the rubber (because of damages to it's ecosystem through the flood), there would be a limited supply, and a substancial drop on synthetic polymers.


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3 0
3 years ago
Read 2 more answers
Identify the species oxidized, the species reduced, the oxidizing agent and the reducing agent in the following electron transfe
babunello [35]

Answer:

Oxidized and reducing agent: manganese.

Reduced and oxidizing agent: mercury.

Explanation:

Hello!

In this case, for the reaction:

Hg^{2+}(aq) + Mn^0(s)\rightarrow Hg(s) + Mn^{2+}(aq)

We keep in mind that the species that increase the oxidation state is the oxidized one whereas the one that decrease the oxidation state is the reduced one; therefore manganese is the oxidized one as well as the reducing agent because it goes from 0 to +2 and mercury the reduced one as well as the oxidizing agent because it goes from 2+ to 0.

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6 0
2 years ago
• identify early ideas about evolution
Andreyy89
There is two ideas about evolution.

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7 0
3 years ago
Which of the following is a type of physical change.
trapecia [35]

Answer:

B. a change in their state or substance

Explanation:

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6 0
3 years ago
Liquid methanol (CH₃OH) can be used as an alternative fuel in pickup and SUV engines. An industrial method for preparing it invo
r-ruslan [8.4K]

40.6 kJ of heat energy had been emitted.

CO(g) + 2H2(g) CH3OH(l)CO volume, V (CO), equals 15 L or 0.015 m3.

Temperature = 85 0C = 85 + 273 = 358 K Pressure = 112 kPa = 112,000 PaPV = nRT n= 112000 0.015 / 8.314 358 n(CO) = 0.56 moles,

according to the ideal gas law.H2 volume is 14.4 L or 0.0144 m3

T = 750C + 273 K = 348 K n(H2) = 99191.84 0.0144 m3 / 8.314 348 K = 0.49 moles of H2 Pressure = 744 torr = 99191.84 Pa

Hydrogen is the limiting reagent, according to the calculation above.CH3OH = H2 = 0.49/2 = 0.245 m-238.6 (-110.5) = -128.1 kJ/mol for H(rxn) = H(f) (CH3OH) - H (rxn)

We must now multiply H(rxn) by the number of moles of methanol.

E = H(rxn) n(CH3OH) = 128.1 0.245 = 40.6 kJ.

Learn more about Ideal gas law here-

brainly.com/question/13821925

#SPJ4

7 0
2 years ago
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