Based upon the mass of baking soda (NaHCO3) and using an excess of HCl in this experiment, you will 1) determine the mass of CO2
2 answers:
Answer:
1) The mass of produced is 1.29g
2) The theoretical yield for is 1.311g
3) The percent yield is 98.4%
Explanation:
Step 1: in an experiment let's allow sodium bicarbonate (baking soda) to react with hydrochloric acid HCl to obtain high yield .
⇒
from the balanced equation it can be seen that 1 mole of produces 1 mole of
.
Step 2: Let assume 2.5g of were used
mole of = 2.5g/molecular mass of
molecular mass of = 23+1+12+(16×2) = 84g/mol
converting mass of into mole we have:
= 0.0298 moles
Step 3: since :
mole is ratio 1:1, then 0.0298 mole of
will produce 0.0298 mole of
The mass of this amount of = 0.0298 × molecular mass of
= 0.0298 mol × ( 12+(16×2))g/mol = 1.3111g of
therefore; the theoretical yield expected is 1.311g
Step 4: Let assume for the experiment that we obtained 1.29g of as the actual yield
then, percent yield for =
× 100%
= 1.2g/1.311g × 100% =98.4%
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Answer:
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