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siniylev [52]
3 years ago
10

IDENTIFY THE NUMBER OF SIGNIFICANT FIGURES IN EACH OF THESE MEASUREMENTS OF AN OBJECT: 76.47 AND 76.59

Chemistry
1 answer:
murzikaleks [220]3 years ago
8 0

Answer:

they both have 4 sig figs:)

Explanation:

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Individual measurements introduce errors that may be large or small depending on the quality of the tools and processes used. Sc
kirill [66]

Answer:

B. accepted value x 0.1

Explanation:

in the equation provided

Percentage Error=\frac{Error}{AcceptedValue} X100

Maximum allowed value of percentage error = 10%

put this value in the equation in stead of percentage error we get,

10 = \frac{error}{AcceptedValue} X100\\ \frac{10}{100} =\frac{error}{AcceptedValue}\\.1=\frac{error}{AcceptedValue}\\error = .1 X Accepted Value

so maximum error = .1 x accepted value

10 % percentage error means the experimental value has 10 % error compared to accepted value.so error will be 10 % of the accepted value

or .1 times of accepted value

8 0
3 years ago
How are energy and mass connected during the formation of an atom?
ss7ja [257]
Energy is absorbed so, the mass is increased. 
energy is released so, the mass is increased
5 0
4 years ago
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The three greatest Renaissance painters were:
Oksanka [162]
Leonardo de Vinci, Michelangelo, and Raphael.
4 0
3 years ago
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For the reactions system 2H2(g) + S2(g) 2H2S(g), a 1.00 liter vessel is found to contain 0.50 moles of H2, 0.020 moles of S2, an
Mnenie [13.5K]

Answer: 1) 2H_2(g)+S_2(g)\rightleftharpoons 2H_2S(g)

Equilibrium constant is defined as the ratio of the product of concentration of products to the product of concentration of reactants each term raised to their stochiometric coefficients.

K_{eq}=\frac{[H_2S]^2}{H_2]^2\times [S_2]}

where [] = concentration in Molarity=\frac{moles}{\text {Volume in L}}

Thus [H_2S]=\frac{68.5}{1.0}=68.5M

[H_2]=\frac{0.50}{1.0}=0.50M

[S_2]=\frac{0.020}{1.0}=0.020M

K_{eq}=\frac{[68.5]^2}{0.50]^2\times [0.020]}=938450

As the value of K is greater than 1, the reaction is product favored.

2) N_2O_4(g)\rightleftharpoons 2NO_2(g)

K_{eq}=\frac{[NO_2]^2}{[N_2O_4]}

K_{eq}=\frac{[0.500]^2}{[0.0250]}=10

3) N_2+3H_2\rightleftharpoons 2NH_3

K_{eq}=\frac{[NH_3]^2}{[N_2]\times [H_2]^3}

4) Reactions which do not continue to completion are called equilibrium reactions as the rate of forward reaction is equal to the rate of backward direction.


3 0
3 years ago
Read 2 more answers
A particular beer is 65.0% ethanol by volume . If a single bottle of beer contains a total of 750.0 mL of beer, what volume, in
Oksi-84 [34.3K]

The volume in mL of ethanol (C₂H₆O) present in the bottle is 487.5L

HOW TO CALCULATE VOLUME OF ETHANOL:

  • According to this question, a particular beer is 65.0% ethanol by volume. This means that the beer contains 65/100 of ethanol.

  • If a single bottle of beer contains a total of 750.0 mL of beer, the volume of ethanol in the bottle is calculated as follows:

  • = 65/100 × 750

  • = 65 × 7.5

  • = 487.5mL

  • Therefore, volume in mL of ethanol (C₂H₆O) present in the bottle is 487.5L

Learn more at: brainly.com/question/8725232?referrer=searchResults

6 0
2 years ago
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