Answer:
6
Explanation:
Significant figures:
The given measurement have six significant figures 120.090.
All non-zero digits are consider significant figures like 1, 2, 3, 4, 5, 6, 7, 8, 9.
Leading zeros are not consider as a significant figures. e.g. 0.03 in this number only one significant figure present which is 3.
Zero between the non zero digits are consider significant like 104 consist of three significant figures.
The zeros at the right side e.g 2400 are also significant. There are four significant figures are present.
In 120.090 the zero before and after 9 are also significant.
7.8049856 g of aluminium phosphate is produced from 7.5 g of lithium phosphate in this balanced equation.
<h3>What are moles?</h3>
A mole is defined as 6.02214076 ×
of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
Given data:
→ 
Moles of 7.5 g of lithium phosphate.
The molar mass of lithium phosphate is 115.79 g/mol.
Moles = 
Moles =
Moles = 
Moles = 0.06477243285
Now we will compare the moles of
with
.
: 
2 : 2
0.385 : 2÷2× 0.064 = 0.064 mol
Mass of
:
Mass of
= moles × molar mass
Mass of
=0.064 mol × 121.9529 g/mol
Mass of
= 7.8049856 g
Hence, 7.8049856 g of aluminium phosphate is produced from 7.5 g of lithium phosphate in this balanced equation.
Learn more about moles here:
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Answer:
50W
Explanation:
The formula and is
W = F × s
(force x distance)
W= 50 N× 5 m =250 N m=250 J
Done in 5 seconds the power is
p
=
W
t
where
t
=time
p
=
250
J
5
=
50 J
/s
=50 W
Answer:
Explanation:
In this problem,
we will determine the enthalpy at the end of heat input and we get the condition is the super heated state.
so the entropy change will be due to latent heat at 150 kPa and also due to temperature change at the super heated state.
All the temperature, enthalpy is evaluated with the help of the steam table.
mass is calculated with the help of a specific volume at initial condition.
<u>see image below</u>
Answer: 2) see below
3) 2AgCl → 2Ag + Cl₂
<u>Explanation:</u>
2)
Step 1: Crushing & Grinding CuFeS₂(s)→ CuFeS₂(s)
Step 2: Froth Flotation CuFeS₂(s)----> CuFeS₂ (l)
Step 3: Roasting 2CuFeS₂(l) + 3O₂(g) → 2FeO(s) + 2CuS(s) + 2SO₂(g)
Step 4: Converting matte to blister Cu₂S(l) + O₂(g) → 2Cu(l) + SO₂(g)
Step 5: Anode Casting Cu(l) → Cu(s)
Step 6: Electrolytic Refining Cu(s) → Cu(s)
Anode: Cu(s) → Cu₂ + (aq) + 2e-
Cathode: Cu2 + (aq) + 2e- → Cu(s)
<em>see diagram below for illustration of steps</em>
3) When silver chloride (solid) is exposed to sunlight, it decomposes into silver (solid) and chlorine (gas).
The equation is written as: 