Question

Find the equation of a line that passes through the points (1,3) and (2,2).

Answer 1

Answer:

y=-x+4

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(2-3)/(2-1)

m=-1/1

m=-1

y-y1=m(x-x1)

y-3=-1(x-1)

y-3=-x+1

y=-x+1+3

y=-x+4