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3 years ago

7

Given the units of force, write a simple equation relating a constant force Fexerted on an object, an interval of time t during

which the force is applied, andthe resulting momentum of the object,

1 answer:

sattari [20]3 years ago

3 0

newton's second law ...

F=momentum change/time

F = (Final mom'm-start mom'm)/time

Ft+start =final

Ft is impulse

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Which of the following statements about language is true?

ohaa [14]

Answer: Option (c) is the correct answer.

Explanation:

Language is defined as a medium through which a person can deliver its thoughts, ideas, or perceptions to one or more individuals.

For example, Leslie is feeling sad and that is why she is crying. Therefore, listening a cry sound her friend sitting in the next room came immediately to console her.

Hence, sound of crying is also a sign of language that tells Leslie is sad about something.

Therefore, we can conclude that the statement languages use spoken sounds, written words, and signs to represent ideas and events, is true about language.

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3 years ago

During the spin cycle of a washing machine, the clothes stick to the outer wall of the barrel as it spins at a rate as high as 1

Darya [45]

To answer the two questions, we need to know two important equations involving centripetal movement:

v = ωr (ω represents angular velocity <u>in radians</u>)

a = $\frac{v^{2}}{r}$

Let's apply the first equation to question a:

v = ωr

v = ((1800*2π) / 60) * 0.26

Wait. 2π? 0.26? 60? Let's break down why these numbers are written differently. In order to use the equation v = ωr, it is important that the units of ω is in radians. Since one revolution is equivalent to 2π radians, we can easily do the conversion from revolutions to radians by multiplying it by 2π. As for 0.26, note that the question asks for the units to be m/s. Since we need meters, we simply convert 26 cm, our radius, into meters. The revolutions is also given in revs/min, and we need to convert it into revs/sec so that we can get our final units correct. As a result, we divide the rate by 60 to convert minutes into seconds.

Back to the equation:

v = ((1800*2π)/60) * 0.26

v = (1800*2(3.14)/60) * 0.26

v = (11304/60) * 0.26

v = 188.4 * 0.26

v = 48.984

v = 49 (m/s)

Now that we know the linear velocity, we can find the centripetal acceleration:

a = $\frac{v^{2}}{r}$

a = $\frac{49^{2}}{0.26}$

a = 9234.6 (m/ $s^{2}$ )

Wow! That's fast!

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a. 49 (m/s)

b. 9.2 * $10^{3}$ (m/ $s^{2}$ )

If you have any questions on how I got to these answers, just ask!

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2 years ago

A 48.0-kg astronaut is in space, far from any objects that would exert a significant gravitational force on him. He would like t

marusya05 [52]

Answer:

The astronaut is moving at a speed of 0.36m/s

Explanation:

Speed here corresponds to velocity

The astronaut's mass = 48kg

velocity of astronaut = ?

mass of socket = 0.72kg

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mass of the spanner = 0.8kg

velocity of spanner = 8m/s

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mass of the mallet = 1.2kg

velocity of mallet = 6m/s

change in time = 9.9 -0 = 9.9sec

To find the astronaut velocity, we would calculate the total momentum which is the astronaut.

∑momentum (M) = ∑astronaut momentum

∑M = ∑astronaut M

∑astronaut M = M of socket + M of spanner + M of mallet

momentum = mass × velocity

(mass × velocity)of astronaut = (0.72×5) + (0.8×8) + (1.2×6)

48 × velocity of astronaut= 3.6 + 6.4 + 7.2

48 × velocity of astronaut= 17.2

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velocity of astronaut = 0.36m/s

The astronaut is moving at a speed of 0.36m/s

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3 years ago

Two equal charges with magnitude Q and Q experience a force of 12.3442 when held at a distance r. What is the force between two

Pepsi [2]

Answer:197.504 N

Explanation:

Given

Two Charges with magnitude Q experience a force of 12.344 N

at distance r

and we know Electrostatic force is given

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$F=\frac{kQ\cdot Q}{r^2}$

$F=\frac{kQ^2}{r^2}$

Now the magnitude of charge is 2Q and is at a distance of $\frac{r}{2}$

$F'=\frac{k2Q\cdot 2Q}{\frac{r^2}{2^2}}$

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F'=197.504 N

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Maksim231197 [3]

B, C, F are the answers

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