1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
polet [3.4K]
2 years ago
14

An electric dipole is formed from two charges, ±q, spaced 0.800 cm apart. The dipole is at the origin, oriented along the y-axis

. The electric field strength at the point (x,y)=(0cm,10cm) is 400 N/C .
Part A) What is the charge q? Give your answer in nC.
Part B) What is the electric field strength at the point (x, y)=(10 cm, 0 cm) ? Express your answer with the appropriate units.
Physics
1 answer:
Simora [160]2 years ago
3 0

Answer: q = 2.781e-9C = 2.781nC

E=200C

Explanation:

E = Qd/(2πEor^3)

Where

E=Electric field intensity

Q=Charge

d=distance between the dipole=0.008m

Eo=permitivitty

400 N/C = Q(0.80e-2 m)/(2πε*(10e-2 m)^3)

Q= (400* 2* 3.142 * 8.85 x 10-12 * 0.1^3)/0.008

q = 2.781e-9C = 2.781nC

b)

Though the dipole are two separate charges. And since the point is on the x-axis, the electric field strengths are equivalent. The magnitude of the vector sum is:

E = kq*2sin θ/r^2

= 2(8.99e9 N*m^2/C^2)(2.781e-9 C)*sin(arctan(.4/10))/(10e-2 m)^2

= 2(8.99e9) * (2.781e-9) * sin(2.290)/(10e-2 m)^2

=200 C

You might be interested in
The resistance of resistor is greater for:
Monica [59]

Answer:

c: long and thin resistor.

Explanation:

The resistance of a resistor is given by:

R = ρ*L/A

where:

R = resistance

ρ = resistivity (depends on the material)

L =  length of the material

A = cross-sectional area of the material

We can see that the length is on the numerator, which means that if we increase the length, then the resistance is increased.

We also can see that the cross-sectional area is on the denominator, then if we increase the area (for example, with a ticker resistor) the resistance decreases.

Then if we want to maximize the resistance, we need to have a long and thin resistor, so the correct answer is c.

8 0
3 years ago
You accidentally drop an eraser out of the window of an apartment 15 m above the ground
docker41 [41]

Answer:

hello, yes or nou sorry jaja

3 0
2 years ago
Un trineo de 20 kg descansa en la cima de una pendiente de 80 m de longitud y 30° de inclinación. Si µ = 0.2, ¿cuál es la veloci
Mariulka [41]

Answer:

v= 26.70 m/seg

Explanation:  Ver anexo ( diagrama de cuerpo libre)

De acuerdo a la segunda ley de Newton

∑ F  =  m*a

∑ Fx  =  m* a(x)             ∑ Fy  =  m* a(y)

También sabemos que el coeficiente de roce dinámico es:

  μ  = 0.2 = F(r)/N            siendo N la fuerza normal.

Si descomponemos la fuerza P = mg  =  20Kg* 9.8m/seg²

P =  196 [N]    en sus componentes sobre los ejes x y y tenemos

Py  =  P* cos30  =  196* √3/2  =  98*√3

Px  = P* sen30   =  196*1/2  =  98

La sumatoria sobre el eje y es :

∑ F(y)  =  m*a         Py  - N  = 0          98*√3  = N       ( no hay movimiento en la dirección y)

∑ F(x)  = m*a    P(x)  -  Fr  =  m*a

Fr  =   μ *N  =  0.2* 98*√3

Fr  =  19.6*√3  [N]

98 -  19.6*√3  =  m*a

98  -  33.52  = m*a

a =  (98  -  33.52 ) / 20

a = 3.22 m/seg²

Para calcular la velocidad del trineo al pié del plano, sabemos que al pié del plano el trineo ha recorrido 80 m, y que de cinemática

v²  =  v₀²  +  2*a*d             ( se pueden chequear unidades para ver la consistencia de la ecuación  v  y  v₀    vienen dados en m/seg  entonces  v²  y  v₀²  vienen en m²/seg²,  el producto de a (m/seg²) por la distancia d (m) resulta en m²/seg²  entonces es consistente la relación

v²   =  0   +  2*3.22*80       ( la velocidad inicial es cero)

v²  = 515.2  m²/seg²

v  =  √515.2  m/seg

v= 26.70 m/seg

6 0
2 years ago
Please help I’ll give brainliest
lara [203]
I think the answer is B
6 0
2 years ago
Why does a projectile fired along a horizontal not follow a straight path?​
Stella [2.4K]

Answer: A projectile which is fired horizontally is being constantly acted upon by acceleration due to gravity, acting vertically downwards. Hence, it does not follow a straight line path. Also Why a projectile fixed along the horizontal not follow a straight line path? Because the projectile fired horizontally is constantly acts upon by acceleration due to gravity acting vertically downwards.

Explanation:

Hope this helped :)

3 0
3 years ago
Other questions:
  • series RC circuit is built with a 15 kΩ resistor and a parallel-plate capacitor with 18-cm-diameter electrodes. A 18 V, 36 kHz s
    11·1 answer
  • You want to capture and digitize an analog signal that has a frequency bandwidth of 5500 Hz. You select a sampling rate of 5500
    6·1 answer
  • One complete wave passes a putrefying pile of poached pickerel in 0.50 seconds. The piled pickerel protrude 20 cm along the beac
    10·1 answer
  • The origin of an x axis is placed at the center of a nonconducting solid sphere of radius R that carries a charge +qsphere distr
    15·1 answer
  • What is being despited in this picture
    15·1 answer
  • An old woman is worried about time. She walks at a rate of 2 meters per second and travels a
    10·2 answers
  • A ball is thrown into the air with a vertical velocity of 50 m/s and a horizontal
    8·1 answer
  • Why do bones weaken as a person gets older
    5·1 answer
  • 2. In a race, if a runner starts and stops at the same position, what is their<br> displacement? *
    10·1 answer
  • 50 points for 5 questions p.s if u get brainliest u get 50 moe and then u have 100 SO YAAAAAAY p.s dont answer the new one i for
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!