Answer:
In 15 minutes the car travels a distance of 15 km.
Explanation:
Answer:
<em>option</em><em> A</em>
Explanation:
the diameter is twice the length of the radius
hope it helps
Answer:
a) 1.248 rad/s
b) 13.728 m/s
c) 0.52 rad/s^2
d) 17.132m/s^2
Explanation:
You have that the angles described by a astronaut is given by:

(a) To find the angular velocity of the astronaut you use the derivative og the angle respect to time:
![\omega=\frac{d\theta}{dt}=\frac{d}{dt}[0.260t^2]=0.52t](https://tex.z-dn.net/?f=%5Comega%3D%5Cfrac%7Bd%5Ctheta%7D%7Bdt%7D%3D%5Cfrac%7Bd%7D%7Bdt%7D%5B0.260t%5E2%5D%3D0.52t)
Then, you evaluate for t=2.40 s:

(b) The linear velocity is calculated by using the following formula:

r: radius if the trajectory of the astronaut = 11.0m
You replace r and w and obtain:

(c) The tangential acceleration is:

(d) The radial acceleration is:

Answer:
27.82m
Explanation:
The distance of the cyclist can be calculated using the formula:
S = ut + 1/2 (at^2)
Where; S = distance
u = initial velocity
a = acceleration
t = time
However, to find acceleration, we use:
a = v - u/t, where v is the final velocity
According to this question, u = 4.2m/s, v = 6.3m/s, t = 5.3s
a = 6.3 - 4.2 / 5.3
a = 2.1/5.3
a = 0.396m/s^2
Hence, using S = ut + 1/2 (at^2)
S = (4.2 × 5.3) + 1/2 (0.396 × 5.3 × 5.3)
S = 22.26 + 5.56
S = 27.82
Therefore, the cyclist travel in 27.82m