The ground is very large an small amount of electric charge wont affect it
To solve this problem it is necessary to apply the concepts related to transformers, that is to say passive electrical device that transfers electrical energy from one electrical circuit to one or more circuits.
From the mathematical definition we have that the relationship between the voltage of the first coil and the second coil is proportional to the number of loops of the first and second loop, that is:

Where
input voltage on the primary coil.
input voltage on the secondary coil.
number of turns of wire on the primary coil.
number of turns of wire on the secondary coil.
Replacing our values we have:



Replacing,


From the same relations of number of turns and the voltage of the first and second coil we also have the relation of electricity and voltage whereby:

Where
= Current Primary Coil
= Current secundary Coil
Therefore:



Therefore the maximum values for the secondary coil of the voltage is 410.56V and Current is 1.87A
Answer:
Explanation:
Given
Mass of object (m)=6 kg
falling height(h)=10 m
mass of water(
)=600 gm
temperature of water =15
specific heat of water 
Let T be the Final Temperature of water
Here Object Potential Energy is converted into Heat energy which will be absorbed by water
Potential Energy(P.E.)
Heat supplied


T-16=0.234

This is not an efficient way of heating water as there is only
increase in temperature.
When you are finding work, the easiest way is to use the formula.
W = F*D
Where F is the force and D is the distance. Simply take the constant force of 209N and multiply it by the distance of 10m. Which will give you 2090J