Answer:
Time is 14.8 s and cannot landing
Explanation:
This is a kinematic exercise with constant acceleration, we assume that the acceleration of the jet to take off and landing are the same
Calculate the time to stop, where it has zero speed
Vf² = Vo² + a t
t = - Vo² / a
t = - 110²/(-7.42)
t = 14.8 s
This is the time it takes to stop the jet
Let's analyze the case of the landing at the small airport, let's look for the distance traveled to land, where the speed is zero
Vf² = Vo² + 2 to X
X = -Vo² / 2 a
X = -110² / 2 (-7.42)
X = 815.4 m
Since this distance is greater than the length of the runway, the jet cannot stop
Let's calculate the speed you should have to stop on a track of this size
Vo² = 2 a X
Vo = √ (2 7.42 800)
Vo = 109 m / s
It is conclusion the jet must lose some speed to land on this track
Answer:
Explanation:
A lot. That's why he was one of Boston's star hitters.
m = 0.15 kg
a = 3.0 * 10^4
F = ?
F = 0.15 * 3*10^4
F = 0.45 * 10^4
F = 4.5 * 10^3 Newtons
You should always express scientific notation as a number between 1 and 10 or 1 < x < 10. The power will determine the exact value of the number expressed as a scientific notation.
In a science lab, there is the adequate availability of raw materials for experiments such as chemicals while outside a science lab there isn't.
In a science lab, the availability of apparatuses and sources of heat is higher than outside a science lab.
<h3>What is science laboratory?</h3>
The science lab is a place where the experiments related to the science background are performed with the use of apparatus.
The science lab has plenty of equipment to perform the experiment whether related to physics or chemistry or biology.
Thus, source of heat and availability of raw material and equipment are the differences between the science activities carried out in a science laboratory and those carried out side of science laboratory.
Learn more about science laboratory.
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