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KatRina [158]
3 years ago
10

How does the first law of motion give definition of inertia​

Physics
2 answers:
horsena [70]3 years ago
6 0

Answer:

Newton first law states that a body at rest remains at rest or if it is motion, remains in motion at a constant unless acted upon by a external force

VikaD [51]3 years ago
5 0
Newton’s first law states that an object will not change its motion unless it is acted on by an unbalanced force, aka law of inertia.
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A car traveling at 60 km/h will skid 30 m when its brakes are locked. if the same care is traveling at 180 km/h, what will be th
Flauer [41]
The first car travels at 60km/h and skid at 30m away from the starting point while another car is also traveling at 180km/h. Now, we need to solve for the skidding distance.
We assigned variables such as:
V1=60km/h
V2=180km/h
Skid1=30m
Skid2=?
We solve this by ratio and proportion method such as shown below:
V1/V2=skid1/skid2
60/180=30/skid2
skid2=(30*180)/60
skid2=90meters

Th answer is 90 meters.
3 0
3 years ago
Read 2 more answers
Can you answer my question please go to my profile ​
ad-work [718]

Answer:

what do u need help on

I went to ur profile and I don't know what I'm looking for

8 0
3 years ago
Read 2 more answers
A Carnot engine has an efficiency of 0.537, and the temperature of its cold reservoir is 379 K.
katen-ka-za [31]

Answer:

(A) Th = 818.6 K

(B) Qh = 14211.7 J

Explanation:

efficiency (n) = 0.537

temperature of cold reservoir (Tc) = 379 K

heat rejected (Qc) = 6580 J

(A) find the temperature of the hot reservoir (Th)

 n = 1 - \frac{Tc}{Th}

0.537 = 1 - \frac{379}{Th}

\frac{379}{Th} = 1 - 0.537 = 0.463        

Th = \frac{379}{0.463}

Th = 818.6 K

(B) what amount of heat is put into the engine (Qh) ?

from \frac{Tc}{Th} = \frac{Qc}{Qh}

Qh = 6580 ÷ \frac{379}{818.6}

Qh = 14211.7 J

8 0
3 years ago
A boat takes off from the dock at 2.5m/s and speeds up at 4.2m/s2 for 6.0 seconds how far has the boat traveled
suter [353]

Answer:

The answer is "91 m"

Explanation:

v_0 = 2.5 \ \frac{m}{s}\\\\a = 4.2\ \frac{m}{s^2}\\\\t = 6.0\ s\\\\\Delta x=?

Using formula:

\Delta x = v_0 t +\frac{1}{2} at^2\\\\

      = 2.5 \times 6.0  +\frac{1}{2}  \times  4.2 \times 6.0^2\\\\= 90.6\  m \approx 91\ m

5 0
3 years ago
Newton's first law states that an object traveling with a constant velocity will remain traveling at a constant velocity unless
VikaD [51]
C. The forces on an object traveling at terminal velocity are balanced.
4 0
4 years ago
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