The first car travels at 60km/h and skid at 30m away from the starting point while another car is also traveling at 180km/h. Now, we need to solve for the skidding distance.
We assigned variables such as:
V1=60km/h
V2=180km/h
Skid1=30m
Skid2=?
We solve this by ratio and proportion method such as shown below:
V1/V2=skid1/skid2
60/180=30/skid2
skid2=(30*180)/60
skid2=90meters
Th answer is 90 meters.
Answer:
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Answer:
(A) Th = 818.6 K
(B) Qh = 14211.7 J
Explanation:
efficiency (n) = 0.537
temperature of cold reservoir (Tc) = 379 K
heat rejected (Qc) = 6580 J
(A) find the temperature of the hot reservoir (Th)
n = 1 - 
0.537 = 1 -
= 1 - 0.537 = 0.463
Th =
Th = 818.6 K
(B) what amount of heat is put into the engine (Qh) ?
from 
Qh = 6580 ÷ 
Qh = 14211.7 J
C. The forces on an object traveling at terminal velocity are balanced.